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UT Arlington PHYS 1441 - Rolling Motion

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PHYS 1441 – Section 501 Lecture #13Angular Displacement, Velocity, and AccelerationHow about the acceleration?Rolling Motion of a Rigid BodyMore Rolling Motion of a Rigid BodyTorqueExample for TorqueMoment of InertiaTorque & Angular AccelerationRotational Kinetic EnergyExample for Moment of InertiaKinetic Energy of a Rolling SphereAngular Momentum and Its ConservationEffect of Angular Momentum ConservationExample for Angular Momentum ConservationSimilarity Between Linear and Rotational MotionsConditions for EquilibriumMore on Conditions for EquilibriumExample for Mechanical EquilibriumExample for Mech. Equilibrium Cont’dExample 9 – 9Example 9 – 9 cont’dSlide 23How do we solve equilibrium problems?Elastic Properties of SolidsYoung’s ModulusBulk ModulusExample for Solid’s Elastic PropertyDensity and Specific GravityFluid and PressureExample for PressureSlide 32Wednesday, July 14, 2004 PHYS 1441-501, Summer 2004Dr. Jaehoon Yu1PHYS 1441 – Section 501Lecture #13Wednesday, July 14, 2004Dr. Jaehoon Yu•Rolling Motion•Torque•Moment of Inertia•Rotational Kinetic Energy•Angular Momentum and Its Conservation•Conditions for Mechanical EquilibriumToday’s homework is #6 due 7pm, Friday, July 23!!Remember the second term exam, Monday, July 19!!Wednesday, July 14, 2004 PHYS 1441-501, Summer 2004Dr. Jaehoon Yu2Using what we have learned in the previous slide, how would you define the angular displacement?Angular Displacement, Velocity, and AccelerationHow about the average angular speed?And the instantaneous angular speed?By the same token, the average angular accelerationAnd the instantaneous angular acceleration?When rotating about a fixed axis, every particle on a rigid object rotates through the same angle and has the same angular speed and angular acceleration.ififififtttttlim0dtdififtttttlim0dtdUnit? rad/sUnit? rad/sUnit? rad/s2Unit? rad/s2Wednesday, July 14, 2004 PHYS 1441-501, Summer 2004Dr. Jaehoon Yu3How about the acceleration?v rw=TwoHow many different linear accelerations do you see in a circular motion and what are they?Total linear acceleration isSince the tangential speed v isWhat does this relationship tell you?Although every particle in the object has the same angular acceleration, its tangential acceleration differs proportional to its distance from the axis of rotation.Tangential, at, and the radial acceleration, ar.taThe magnitude of tangential acceleration at isThe radial or centripetal acceleration ar israWhat does this tell you?The father away the particle is from the rotation axis, the more radial acceleration it receives. In other words, it receives more centripetal force.avtD=D( )rtwD=DrtwD=Drrv2 rr22r22rtaa   222rr 42rWednesday, July 14, 2004 PHYS 1441-501, Summer 2004Dr. Jaehoon Yu4Rolling Motion of a Rigid BodyWhat is a rolling motion?To simplify the discussion, let’s make a few assumptionsLet’s consider a cylinder rolling without slipping on a flat surfaceA more generalized case of a motion where the rotational axis moves together with the objectUnder what condition does this “Pure Rolling” happen?The total linear distance the CM of the cylinder moved isThus the linear speed of the CM isA rotational motion about the moving axis1. Limit our discussion on very symmetric objects, such as cylinders, spheres, etc2. The object rolls on a flat surfaceR ss=RRs dtdsvCMCondition for “Pure Rolling”dtdRRWednesday, July 14, 2004 PHYS 1441-501, Summer 2004Dr. Jaehoon Yu5More Rolling Motion of a Rigid BodyAs we learned in the rotational motion, all points in a rigid body moves at the same angular speed but at a different linear speed.At any given time the point that comes to P has 0 linear speed while the point at P’ has twice the speed of CMThe magnitude of the linear acceleration of the CM isA rolling motion can be interpreted as the sum of Translation and RotationCMaWhy??PP’CMvCM2vCMCM is moving at the same speed at all times.PP’CMvCMvCMvCM+PP’CMv=Rv=0v=R=PP’CM2vCMvCMCMvtD=DRtwD=DRWednesday, July 14, 2004 PHYS 1441-501, Summer 2004Dr. Jaehoon Yu6TorqueTorque is the tendency of a force to rotate an object about an axis. Torque, , is a vector quantity.Magnitude of torque is defined as the product of the force exerted on the object to rotate it and the moment arm.FdLine of ActionConsider an object pivoting about the point P by the force F being exerted at a distance r. PrMoment armThe line that extends out of the tail of the force vector is called the line of action. The perpendicular distance from the pivoting point P to the line of action is called Moment arm.When there are more than one force being exerted on certain points of the object, one can sum up the torque generated by each force vectorially. The convention for sign of the torque is positive if rotation is in counter-clockwise and negative if clockwise. d2F2212211dFdF sinrF FdWednesday, July 14, 2004 PHYS 1441-501, Summer 2004Dr. Jaehoon Yu7R1Example for TorqueA one piece cylinder is shaped as in the figure with core section protruding from the larger drum. The cylinder is free to rotate around the central axis shown in the picture. A rope wrapped around the drum whose radius is R1 exerts force F1 to the right on the cylinder, and another force exerts F2 on the core whose radius is R2 downward on the cylinder. A) What is the net torque acting on the cylinder about the rotation axis?The torque due to F1111FRSuppose F1=5.0 N, R1=1.0 m, F2= 15.0 N, and R2=0.50 m. What is the net torque about the rotation axis and which way does the cylinder rotate from the rest?R2F1F2and due to F2222FRUsing the above result21So the total torque acting on the system by the forces is2211FRFR The cylinder rotates in counter-clockwise.2211FRFR mN - 5.250.00.150.10.5Wednesday, July 14, 2004 PHYS 1441-501, Summer 2004Dr. Jaehoon Yu8Moment of Inertia Rotational Inertia:What are the dimension and unit of Moment of Inertia?iiirmI22mkg  2MLMeasure of resistance of an object to changes in its rotational motion. Equivalent to mass in linear motion.Determining Moment of Inertia is extremely important for


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UT Arlington PHYS 1441 - Rolling Motion

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