we have learned Integrationyubstitutionn indefinite integral definite integral NEW solve by u substitution There are two methods to find integration looks like chain rule U sub by parts 100k fike gyro g let u du 1 2x d 5 d 444 C IRH No chain rule No Product Rule No Quotient Rule fffffggf f 91 1 fix g x 1 7 173 I S 2xeidx se zxdx at u x du 2 dx Se du C e e ex f 1m ax Uta Inx da dx flinxi dx I u du 36 C In texts 3 2 at a 3H du 3 d ex site dx bta x 1 4 3 4 du x dx be 3 2e 1 dx u du f 3 4 C 31 3 116 Se x dx Se du feudu e t c C e g tedx S 2 2 8 15 At U 2 2 8 1 8 dx du 4 du 41 2 dx 2 x dx tXtt ex f x2Hdu2xdx dx if I d In ultc InI H ex f 3 3 let u au 3du 3yd d dx if lildx du In ul th 34 3 316 land xdxUtU ex f ftp f 3 Sx 5dx at a du Edu dx Ida flatulte 4 4135176 can 51 2 2 31EHldx let u R 2 abdu f u7 C i 2x5 du du 21xtildx fi Idu 3 2 dx xtAdX 2 dx 2 1 dX a S 51 4 35 Tax 1 4 I 4 2u du C 21 4 3161 a f 2 dx let u du du x 2 0 2 dX f 2xdx Se du C e e
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