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Current Score : 13 / 15 Due : Friday, May 10, 2019 11:59 PM EDT1. 1/1 points | Previous AnswersSCalcET8 10.4.001.Find the area of the region that is bounded by the given curve and lies in the specified sector.52(e−(π10)−e−(π5)) 2. 1/1 points | Previous AnswersSCalcET8 10.4.002.Find the area of the region that is bounded by the given curve and lies in the specified sector.3π8+9√316 3. 1/1 points | Previous AnswersSCalcET8 10.4.007.Find the area of the shaded region.41π4 4. 2/2 points | Previous AnswersSCalcET8 10.4.010.10.4 (Homework)samantha OhMath 142 LR-X, section LR-X, Spring 2019Instructor: Kathlene HockadayWebAssignLast Saved : n/a Saving... ()r = e−θ/10, π/2 ≤ θ ≤ πr = 3 cos(θ), 0 ≤ θ ≤ π/6r = 4 + 3 sin(θ)Sketch the curve. Find the area that it encloses. 33π2 r = 4 − sin(θ)5. 2/2 points | Previous AnswersSCalcET8 10.4.013.Graph the curve. Find the area that it encloses. 192π r = 3 + sin(4θ)6. 1/1 points | Previous AnswersSCalcET8 10.4.019.Find the area of the region enclosed by one loop of the curve.π32 7. 1/1 points | Previous AnswersSCalcET8 10.4.024.Find the area of the region that lies inside the first curve and outside the second curve.49π4+98 8. 0/1 points | Previous AnswersSCalcET8 10.4.028.Find the area of the region that lies inside the first curve and outside the second curve.40π−35√3 9. 1/1 points | Previous AnswersSCalcET8 10.4.029.Find the area of the region that lies inside both curves.9π8−94 r = sin(8θ)r = 7 − 7 sin(θ), r = 7r = 19 sin(θ), r = 10 − sin(θ)r = 3 sin(θ), r = 3 cos(θ)10.1/1 points | Previous AnswersSCalcET8 10.4.031.Find the area of the region that lies inside both curves.π2−1 11.1/1 points | Previous AnswersSCalcET8 10.4.035.Find the area inside the larger loop and outside the smaller loop of the limaçon 3√3+π4 12.1/1 points | Previous AnswersSCalcET8 10.4.050.Find the exact length of the curve. Use a graph to determine the parameter interval.4 13.0/1 points | Previous AnswersSCalcET8 10.4.047.Find the exact length of the polar curve.163((π2+1)(32)−1) r = sin(2θ), r = cos(2θ)r = + cos(θ).12r = cos2(θ/2)r = θ2, 0 ≤ θ ≤

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