UB PHY 151 - Experiment M6: Conservation of Momentum
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Sophia Tronolone PHY 151 Lab VI 1 Sketch of the apparatus 10 11 23 Recorded Speeds cm s Speed gate 1 cm s Speed gate 2 cm s Trial 1 Initial Final Initial Final 1 2 3 4 5 6 7 8 9 10 31 6 35 5 40 8 32 5 29 4 38 7 39 8 38 0 33 8 46 5 14 4 19 9 19 7 27 4 15 0 28 4 31 5 26 3 22 7 26 6 18 9 31 1 32 0 38 3 20 4 41 6 45 6 38 6 33 6 36 9 20 0 22 9 27 6 19 9 20 7 25 0 25 9 25 1 21 5 36 4 The mass of both gliders in VI 1 were 153 1g To do the calculations for momentum and kinetic energy I converted all units to SI units For example because 1 kg 1000g I converted 153 1g to kilograms which gave me 0 1531kg for both gliders for VI 1 I also used the conversion factor of 1 m 100 cm in order to convert cm s to m s To find momentum I used the equation P mv P stands for momentum m is the mass in kg and v is the velocity in m s This equation is sampled below To calculate the change in momentum I used the formula sampled below To calculate the change of momentum over the initial momentum I used the rearranged formula sampled below Excel calculated the values for rest below is the table of momentum calculations Momentum Table Pi kg m s 0 0773 0 102 Pf kg m s 0 0527 0 0655 P kg m s 0 13 0 168 P Pi 1 68 1 647 0 111 0 108 0 0762 0 123 0 131 0 117 0 103 0 128 0 0724 0 0724 0 0547 0 0818 0 0879 0 0787 0 0677 0 0965 0 183 0 180 0 131 0 205 0 219 0 196 0 171 0 225 1 648 1 666 1 719 1 666 1 6717 1 6752 1 660 1 7578 To find kinetic energy I used the equation KE 1 2mv 2 KE stands for kinetic energy m stands for mass in kg and v is velocity in m s This is shown in a sample calculation below To calculate the change in momentum the formula is To calculate the change in kinetic energy over the initial kinetic energy I divided the values sampled below Excel calculated the values for the rest below is the kinetic energy calculations within the table Kinetic energy calculations KEi J 0 01037 0 01705 0 02058 0 01931 0 009802 0 02471 0 02804 0 02245 0 01738 0 02697 KEf J 0 004649 0 007045 0 008802 0 008778 0 00500 0 01095 0 01273 0 01011 0 007483 0 01555 VI 2 Sketch of the apparatus KE J 0 005721 0 010005 0 011778 0 010532 0 004802 0 01376 0 01531 0 01234 0 009897 0 01142 KE KEi 0 5517 0 5868 0 5723 0 5454 0 4899 0 5568 0 5460 0 5496 0 5694 0 4234 Recorded speeds in cm s Speed gate 1 cm s Speed gate 2 cm s Trial 1 2 Initial 24 8 27 4 Final 9 0 9 0 Initial 25 7 26 9 Final 28 1 31 6 3 4 5 6 7 8 9 10 38 1 36 7 42 9 41 8 34 6 32 5 26 8 28 9 11 2 11 3 15 5 17 0 13 1 9 3 9 7 10 0 35 2 37 1 46 7 50 0 36 4 28 0 37 7 36 2 48 0 46 2 56 4 55 8 44 6 39 8 29 9 32 4 The mass for glider 1 is 153 1 and the mass for glider 2 is 282 1 Similar to VI 1 in order to do my calculations for momentum and kinetic energy I converted all units to SI units An example is written below as it was for VI 1 using all conversion factors The calculations for momentum are the same as VI 1 and excel calculated the values for the rest Momentum calculations Pi kg m s Pf kg m s 11 04685 11 78343 9 30491 10 29226 P kg m s 20 35176 22 07569 P Pi 1 842313 1 873451 The calculations for kinetic energy are the same from VI 1 Excel calculated the values for the rest 15 76303 16 08468 19 74206 20 50458 15 5657 12 87455 14 73825 14 63661 15 25552 14 76305 18 28349 18 34388 14 58727 12 65141 9 91986 10 67104 31 01855 30 84773 38 02555 38 84846 30 15297 25 51596 24 65811 25 30765 Kinetic energy calculations KEi J KEf J KE J 140 2434265 159 5358685 285 8873375 297 24706 448 49792 486 376222 278 528206 191 4391375 255 4542265 248 7728875 117 5750405 22 668386 147 047438 12 4884305 334 581632 48 6942945 310 8374315 13 5903715 467 0655455 18 5676255 461 301872 25 07435 293 7077635 15 1795575 230 0496515 168 389486 133 3027 122 1515265 155 723648 93 0492395 VI 3 1 967803 1 917832 1 926118 1 894623 1 937141 1 981891 1 673069 1 729064 KE KEi 0 161635997 0 078279766 0 170326867 0 045720794 0 04139958 0 051553404 0 054499175 0 879598018 0 478173832 0 37403288 Sketch of apparatus This time the magnets on m1 and m2 gliders are attached to one another with sticky tape making the gliders move as one Recorded speeds cm s Speed gate 1 cm s Speed gate 2 cm s Trial Initial Final Initial Final 1 2 3 4 5 6 7 8 9 10 53 1 56 8 54 6 58 8 57 8 55 8 49 7 52 6 54 5 59 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 46 5 56 8 51 8 46 7 46 5 58 8 32 1 57 4 37 4 38 6 11 8 16 3 11 2 13 3 37 1 9 1 27 9 13 3 8 8 12 2 The mass for glider 1 is 146 7 and the mass for glider 2 is 276 1 Similar to VI 1 in order to do my calculations for momentum and kinetic energy I converted all units to SI units An example is written below as it was for VI 1 using all conversion factors The calculations for momentum are the same as VI 1 Excel calculated the values for the rest Momentum calculations Pi kg m s Pf kg m s P kg m s P Pi 20 62842 24 01504 22 3118 21 51983 21 31791 24 42054 16 1538 23 56456 18 32129 19 37144 3 25798 4 50043 3 09232 3 67213 10 24331 2 51251 7 70319 3 67213 2 42968 3 36842 23 8864 28 51547 25 40412 25 …

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# UB PHY 151 - Experiment M6: Conservation of Momentum

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