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mt g vs ms g Teflon pan y 0 36x 6 136 0 200 400 800 1000 1200 600 mt g mp Teflon pan 62 6 g mp Rubber bottom pan 126 7 g m g 200 200 200 200 200 400 400 400 400 400 600 600 600 600 600 800 800 800 800 800 1000 1000 1000 1000 1000 1 g s m 450 400 350 300 250 200 150 100 50 0 ms g 80 110 90 100 120 120 140 150 180 150 240 200 250 250 210 280 320 300 300 300 360 380 380 400 400 mt g 262 6 262 6 262 6 262 6 262 6 462 6 462 6 462 6 462 6 462 6 662 6 662 6 662 6 662 6 662 6 862 6 862 6 862 6 862 6 862 6 1062 6 1062 6 1062 6 1062 6 1062 6 mp m 62 6 200 262 6 g Using Linest S S 0 36 6 136 0 013875 9 996312 B B So b y mx b and is the coefficient of friction Since and Then 0 0139 ms g 120 120 120 140 100 200 200 200 180 220 260 240 280 240 260 300 300 320 340 340 380 340 360 360 360 mt g 226 7 226 7 226 7 226 7 226 7 326 7 326 7 326 7 326 7 326 7 426 7 426 7 426 7 426 7 426 7 526 7 526 7 526 7 526 7 526 7 626 7 626 7 626 7 626 7 626 7 2 m g 100 100 100 100 100 200 200 200 200 200 300 300 300 300 300 400 400 400 400 400 500 500 500 500 500 Linest S S 0 6 4 82 0 025133 11 29778 B B m g 200 400 600 800 1000 mt g 262 6 462 6 662 6 862 6 1062 6 H cm 34 7 35 7 38 3 37 9 42 4 y cm 18 4 19 4 22 21 6 26 1 k rads 0 177859 0 179759 0 187638 0 189871 0 213149 0 216436 0 209215 0 212322 0 253673 0 259259 3 L 104 cm d 16 3 cm Y H d Example Y 34 7 16 3 18 4 cm Example arcsin arcsin 18 4 104 arcsin 0 1769 0 1778 rads According to manual k Example k ta n 0 1778 0 1796 Standard deviation found through excel 0 030746 4 Same equations as the ones used in question 3 m g 200 400 600 800 1000 mt g 326 7 526 7 726 7 926 7 1126 7 H cm 45 3 49 4 45 45 2 47 4 y cm 29 33 1 28 7 28 9 31 1 k rads 0 282592 0 290363 0 323903 0 335727 0 27959 0 28711 0 281591 0 289278 0 303685 0 313378 k 0 303171 Standard deviation 0 02109


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UB PHY 151 - Study Guide

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