Daily Handout Week 4 Day 4 Topics: Statics Submit to Blackboard by 11:59 pm. Upload to W4D4-HO Folder 1. A 5 kg beam is 20 cm long and has a uniform density. It is balanced on two points as shown. (a) Draw an extended free body diagram, showing where each force acts. There will be three forces acting on the beam. (b) Use sum of torques to find the normal force acting on the block at the right-hand point in a single equation. As part of your answer, state what you chose as your pivot point and why. Answers: 39.2 N (c) Use the sum of forces, along with your answer to part (b), to find the normal force acting on the block at the left-hand point. Give your answer in newtons. Answer: 9.81 N (d) Now let's see what happens when we change the pivot point... Repeat this problem, but now use the sum of torques with the right-hand point as the pivot. Use this to calculate the normal force acting on the block at the left-hand point in a single equation. Did changing the pivot point impact your answer? Should it?2. A 40.0 kg, 5.00 m long uniform horizontal beam is supported by, but not attached to, the two vertical posts. The vertical posts are separated by 3.00 m. A 25.0 kg girl starts walking along the beam to the right. (a) Determine an expression for the normal force (N1) exerted on the beam by the left vertical post when the girl is a distance x to the right of the right vertical post. The result should be N1 written as a function of x (be sure to include units). Answer:N1(x)= 65.4 N − (81.8 N/m)x (b) What is the maximum distance to the right of the right vertical post (xmax) she can walk before the beam begins to tip? Answer:xmax= 0.8 00 m x3.00