EXSS 376L: PHYSIOLOGICAL BASIS OF HUMAN PERFORMANCELAB 2: ANAEROBIC POWER FIELD ASSESSMENTSANAEROBIC POWER DATA COLLECTION SHEET (Place your information here)1. SUBJECT 1:Jonathan Sinclair Gender:__Male_____ Age:_20_Height:___176.3_____cm Wt: ___76.2_____kg2. PHYSICAL ACTIVITY and DIET SELF-REPORT:a. Do you feel well rested today? Yes Nob. Did you eat breakfast and/or lunch at least 1-2 hours prior to this class? Yes Noc. How would you currently classify yourself? (Please circle one answer only)Sedentary (S) Active (A) Recreational Athlete (RA) College Athlete (CA)What type of physical activity/sport do you tend to excel in? Soccer3. TEST RESULTS. Record data to nearest tenth of a second or nearest 0.5 cm. Circle the“best” trial result. Use the best trial for calculations and discussion.Vertical Jump (Vertical Power)Reach Height: ___7’ 2.2’’__Trial 1: ___7’ 7’’______ Trial 2:___7’6’’___ Trial 3: __7’7’’____Best Trial – Reach Height: ___7’ 7’’_____Convert to cm:_____234.69cm_____40 yard dash (Speed)Time(s) 1: __4.51s____ Time(s) 2:__4.68s_____ Time(s) 3:___4.63s___Best Trial: ____4.51_________sMedicine Ball Throw (Upper-body power)My BEST Seated Two-Hand Chest Pass Medicine Ball Throw distance was_______172_________ (total inches). - 436.88cmStanding Long Jump (Horizontal Power)My BEST Standing Long Jump Distance was______67_____ (inches) - 170.18 cmEquations for Calculations:Vertical JumpVerticalDifference=JumpHeight(cm)−ReachHeight(cm)= 234.69 - 220.06= 14.6340 Yd Sprinta. Determine the horizontal velocity in m/sec of the best sprint trial:v = D/t ( v = velocity (m/s), D = distance run (meters), t = time in sec(s))= 36.58/4.51= 8.11 m/sb. Determine the power in kgm/s generated for the best sprint trial:P = BW * v= 76.36 kg * 8.11 m/s= 619.28 kgm/swhere: P = power (kgm/s); BW = body weight (kg); v = velocity (m/s)c. Convert P from kg*m/s to Watts (You need to figure out how to accomplish this stepon your own)` 1 kg-m/s = 9.81 Watts619.28 kgm/s * 9.81 Watts = 6075.14 wattsAbsolute to Relative ConversionDivide Watts by weight in kg to determine relative power (W/kg)6075.14 watts/ 76.36 kg = 79.55 W/kgDISCUSSION QUESTIONSUsing the calculations on the previous page, calculate the absolute and relative power for boththe vertical and the 40 yd sprint. Show calculations of your values.1. (10 points) Plot the 4 following bar graphs: (1) 40 yd sprint comparing male and femalemean absolute power values; (2) 40 yd sprint comparing male and female mean relative powervalues; (3) vertical jump comparing male and female mean absolute power values; and (4)vertical jump comparing male and female mean relative power values. Using your data, discussthe difference between an absolute versus a relative value and why this distinction may beimportant. Make sure to appropriately label your graphs.The relative graph bridges the gap between the two groups by displaying the data after removingthe body weight from the equation. The weight of an individual has an effect on their strengthsince the heavier they are, the more force they can exert. Males often weigh more than females,making them more likely to use more energy during activity.2. (5 points) What energy systems contributed to your sprint performance? What if thedistance were 800 meters? What about 5000 meters? How does workout intensity and durationrelate to energy systems used?Since my time was roughly 4.51 seconds when sprinting, I relied on ATP hydrolysis andATP-PCr activities, which are both stored and immediately available within the muscle. If thedistance was 800 meters, I would use a combination of anaerobic and aerobic metabolicprocesses, with the anaerobic metabolic processes taking precedence. This is due to the fact thatit is a middle-distance sprinting workout. Thus, for the speedier elements (the sprint at thefinish), anaerobic glycolysis, and aerobic glycolysis, I would use ATP-PCr and ATP hydrolysis.Because it is an endurance event, I would largely use aerobic glycolysis during the 5000 meters.As the intensity and duration of workouts grow, the body switches to aerobic glycolysis becauseanaerobic metabolic processes can.3. (5 points) Compare the value of your vertical jump and standing long jump to class dataand/or normative data. How do you compare? Was your value higher or lower? What might youdo to improve your values or the values of a patient/athlete?My vertical leap is on the higher end of the spectrum when compared to the rest of the class, witha best attempt of 234.69 cm. With a height of 170.18 cm, the long jump was also placedrelatively high. Where body weight and power play a key influence, my vertical and long jumpwere on average higher than females, but I was comparatively high in the vertical compared tomales while being ordinary in the long jump. The lack of experience in the target exercise couldhave played a significant part in my jump distance, and repetition will undoubtedly help meimprove my numbers. Another factor could be that I don't do as much leg work as I