TAMU
MATH 152 -
Torque and Cross-Product
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a ⇥ b a b a = ha1,a2,a3i b = hb1,b2,b3i a ⇥ b =hx1,x2,x3ia b R3a ⇥ b =|a ⇥ b| =a ⇥ b a = i +2j k b =3i j +7kP (1, 0, 1),Q(2, 4, 5), R(3, 1, 7)4PQRa = h2, 3, 2i, b =h1, 1, 0i, c = h2, 0, 3iA(1, 0, 1),B(2, 3, 0),C( 1, 1, 4), D(0, 3, 2)AB, AC, ADa, b, c(a ⇥ b) · c (a · b) ⇥ c (a · b)c (a ⇥ b) ⇥ ca· (b ⇥ c)a, b, c = b aa ⇥ b = 0a⇥ b(a ⇥ b) · c =0 b ⇥ (a ⇥ c)
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