Sunday, March 8, 2015ECE120 HW7 1. a) b) For inputs bc = 00, output is 0; For inputs bc = 01, output is a’; For inputs bc = 10, output is 1; For inputs bc = 11, output is a’.1 0 1 1 1 0 0 0 1 a b cf011100100a’1a’ b cfSunday, March 8, 2015 c) 8 is needed in Part a); 4 is needed in Part b).2. a) O5 = A0A1’A1E b) c) 2Sunday, March 8, 20153. a) Z = l0S2’S1’S0’E + l1S2’S1’S0E + l2S2’S1S0’E + l3S2’S1S0E + l4S2S1’S0’E + l5S2S1’S0E + l6S2S1S0’E + l7S2S1S0E b) c)3Sunday, March 8, 20154. 4S1S0S3S2T3(S0,S1,S2,S3) 0 0 0 0 0 0 0 0 1 1 1 1 0 1 1 1S1S0S3S2T2(S0,S1,S2,S3) 0 0 0 0 1 1 1 1 1 0 0 0 0 1 1 1S1S0S3S2T1(S0,S1,S2,S3) 0 0 1 1 0 0 1 1 0 1 0 1 0 1 0 1S1S0S3S2T0(S0,S1,S2,S3) 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1
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