Friday, February 27, 2015ECE120 HW61. a) Prime implicants x’z’, w’x’y’, wyz x’y’, w’x’, y’z b) Essential prime implicants | x’y’1Friday, February 27, 2015 c) f = x’z’ + w’x’y’ + wyz g = x’y’ And they are both unique. Because for f all the prime implicants are essential, and for g, prime implicants other than the essential one contain don’t care terms.2. a) wx + x’z + ywz = ((((((wx)’)’)’ (((x’z)’)’)’)’)’ (((ywz)’)’)’)’ b) z(x + yw + y'x)(w + y'x + w’z) = ((z(((((x’(((yw)’)’)’)’)’(((y’x)’)’)’)’ ((w’(((y’x)’)’)’)’(((w’z)’)’)’)’)’)’)’)’ c) z + (wxy)’ = (z’((((wx)’)’y)’)’)’3. a) b) G3G2G1G0Xs3Xs2Xs1Xs000000011000101000010010100110110010001110101100001101001011110101000101110011100101011012 0 0 x 1 0 1 x 1 0 1 x x 0 1 x 1 0 1 x 0 1 0 x 1 1 0 x x 1 0 x 1Xs3Xs2Friday, February 27, 2015 c) 3 1 1 x 1 0 0 x 0 1 1 x x 0 0 x 0 1 1 x 1 0 0 x 0 0 0 x x 1 1 x 1Xs1Xs0POS = (G1 + G0’)(G1’ + G0)SOP = G1’G0’ + G1G0POS = G0’SOP = G0’POS = (G3 + G2)(G3 + G1 + G0)SOP = G3 + G2G0 + G2G1POS = (G2 + G1 + G0)(G2’ + G0’)(G2’ + G1’)SOP = G2G1’G0’ + G2’G0 + G2’G1Friday, February 27, 2015 d) 4SOPPOSFriday, February 27, 2015 e) 5SOP with NANDPOS with NORFriday, February 27, 20155. a) b) ai* = aik1’k0’ + ai’k1k0 + aik1k0’ bi* = bik0 + bi’k1k0’ c) 6 0 1 0 0 1 0 0 10 1 0 0 0 1 0 1 1 00