CHEM 102 1nd Edition Lecture 24 Outline of Last Lecture Outline of Current Lecture I. Conjugate Base PairsII. SaltsIII. Acid-Base ReactionsIV. pH of SaltV. SummaryCurrent LectureI. Conjugate Base Pairsa. For any conjugate acid-base pair, Kb x Ka = Kwb. Value for acid ionization constant HCN is 4.0e-10c. We can find CN-:i. CN- + H20 <-> HCN + OH-ii. Kb = Kw/Ka = 1e-14/4e-10 = 2.5e-5d. A conjugate pair differs by H+Ka KbStrong Acid Neutral pHWeak Acid Weak BaseNeutral pH Strong Basee.II. Saltsa. Ionic compounds formed when an acid and base reactb. If solube, strong electrolyte dissociates 100% in waterc. Most of the time they hydrolyze to alter pHIII. Acid-Base Reactionsa. To determine; you have to do the net ionic equationi. HNO3 + NaOH NaNO3 + H20ii. First do molecular, HNO3 + NaOH NaNO3 + H20iii. Next total ionic, H+ + NO3- + Na+ + OH- Na+ + NO3- H20iv. Final net ionic, H+ + OH- H20IV. pH of Salta. When NaC2H3O2 is dissolved, dissociates into: NaCH3COO Na+ + CH3COO-b. Then determine if cation or anion will react with waterc. Cation is neutral CH3OO is basic because its parent was a conjugate of a weak acidThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.d. Therefore the CH3OO will reacte. Then determine the reaction with CH3COO- with H20f. C2H3O2- + H20 2HC2H3O2 + OH-V. Summarya. A reaction with Strong Acid and Strong Basel the solution will be neutralb. A reaction with Weak Acid and Strong Base the solution will be basicc. A reaction with Strong Acid and Weak Base the solution will be acidicd. A reaction with a Weak Acid and Weak Base the solution will varyi. If Kb = Ka; neutralii. If Kb>Ka; basiciii. Kb<Ka;
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