DOC PREVIEW
TAMU CHEM 102 - Temperature Range of Spontaneity and Kinetics
Type Lecture Note
Pages 2

This preview shows page 1 out of 2 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 2 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 2 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

CHEM 102 1nd Edition Lecture 10 Outline of Last Lecture I. Calculation ΔS Equations- Example- Natural TendenciesII. Joshua GibbsIII. ΔG Energy Change- ΔG EquationOutline of Current Lecture I. Determining ΔG, ΔS, and ΔHII. Temperature Range of Spontaneity III. Entropy of SurroundingsIV. Predicting Boiling PointsV. Entropy Phase ChangesVI. KineticsCurrent LectureI. Determining ΔG, ΔS, and ΔH- Solid KNO3 dissolves in water at Room Temperature and ΔG is positive; which is trueo ΔG=0o ΔS>0o ΔS<0o ΔG>0 ΔH is positive, you know that because it is given ΔG is negative, you know that because heat is not added to make the KNO3 dissolves ΔS is positive, you know that because heat is not added- You can also use Gibbs Equation- ΔG = ΔH – TΔS- (-) = (+) – (x)- In order for ΔG to be negative ΔS has to be positiveII. Temperature Range of Spontaneity - To find when the equation will change spontaneity, plug in G=0 which means thesolution is in equilibrium right between spontaneity and nonspontaneity- If the equation is following the natural tendencies, then you want the temperature to be above what you calculated in order for it to spontaneousThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.o ΔG = ΔH – TΔSo 0 = ΔH – TΔSo T = Δ HΔ S=−150−0.60=250 K ∨−23 ° Co Because S was -0.60, for the equation to be spontaneous, the temperature must be under -23III. Entropy of Surroundings- If ΔG = 0, then TΔS = ΔHo ΔSrxn = QrxnTo ΔSsurr = QsurrTo Qsurr = -Qsys; therefore, ΔSsurr = −ΔHrxnToIV. Predicting Boiling Points- Determine the melting point of solid NaCl where the reaction will be spontaneous- NaCl(s)  NaCl(l)- ΔH = 30.3 kJ *** convert to the same units- ΔS = 28.2 J/L ***convert to the same units; 0.0282 kJo ΔG = ΔH – TΔSo 0 = 30.3 – 0.0282xTo 0.0282T = 30.3o T = 1074 K or 801.46 °Co Spontaneous when T > 801V. Kinetics- Kinetic asks the question if this reaction will happen within the given time frame- Kinetics is the study of the rate of the chemical reactiono How fast are reactants used and products formed- Reaction rate: change of concentration of reactant per product per unit of time- Study of mechanisms: sequence of elementary steps that lead to formation of products- React mechanisms: shows how the reaction happens


View Full Document

TAMU CHEM 102 - Temperature Range of Spontaneity and Kinetics

Type: Lecture Note
Pages: 2
Documents in this Course
Load more
Download Temperature Range of Spontaneity and Kinetics
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Temperature Range of Spontaneity and Kinetics and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Temperature Range of Spontaneity and Kinetics 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?