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CU-Boulder PHYS 1120 - Eng Physics 2, Exam I Review

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ECBAA prism-shaped closed surface is in a constant, uniform electric field E, filling all space, pointing right. The 3 rectangular faces of the prism are labeled A, B, and C. Face A is perpendicular to the E-field. The bottom face C is parallel to E. Face B is the leaning face. Which face has the largest magnitude electric flux through it?A)AB) BC) CD) A and B have the same magnitude flux ER2CT 26.2dAn electron is fired into the region of the three charges from the lower right as shown. What is the direction of the acceleration of the electron when it is at point P?xy+Q-Q+QP A B C E = none of these D ER4If we move the point P very far away (x very large, x>>d),we expect the E-field strength to approach...CT 26.4ydd+Q+Q+QxPA) |E| = kQ/x2B) |E| = 3kQ/x2C) |E| = kQ/xD) |E| = kQ/3x2E) |E| = kQER6What is the E-field at point P?A) |E| = 2kQ / s2B) |E| = sqrt(2) kQ / s2C) |E| = kQ / ( sqrt(2) s)2D) zeroE) none of the above. CT 26.6:-Q+Q-Q+QPssssER8What is the E-field at point P?A) |E| = 2kQ / s2B) |E| = sqrt(2) kQ / s2C) |E| = kQ / ( sqrt(2) s)2D) zeroE) none of the above. CT 26.7-Q+2Q-Q+QPssssER9CT 27.9A uniform, infinite plane of + charge creates a uniform E-field  to the plane.E+++++EPoint SPoint THow does the magnitude of the E-field at point S compare with that at point T?A: |E|(S)> |E|(T)B: |E|(S)< |E|(T)C: |E|(S)= |E|(T)ER10CT 27.10Two infinite planes are uniformly charged with the same charge per area . +++++IThe field in region II has magnitude…A: 0 B: E C: 2ED: Depends on where exactly in region IIE: Other/not sureIf only one plane were present, the field due to the one plane would be E.+++++IIIIIER11CT 27.73 closed surfaces enclose a + point charge. A: Small (pink) cubeB: middle (yellow) sphereC: larger (green) sphereWhich surface has the largest flux through it?D: all 3 are sameE: Need more info+ green yellow pink ER12CT 27.18A solid copper sphere of radius A has an excess net charge of +Q. What is the magnitude of the E-field at the center of the sphere?+QA) |E| = kQ/A2B) |E| = 0C) None of theseAER13CT 27.18bA point charge +q sits outside a solid neutral copper sphere of radius A. What is the magnitude of the E-field at the center of the sphere?+qrA) |E| = kq/r2B) |E| = kq/A2C) |E| = kq/(r-A)2D) |E| = 0E) None of theseAER14CT 27.18cA point charge +q sits outside a solid neutral insulating sphere of radius A. What is the magnitude of the E-field at the center of the sphere?+qrA) |E| = kq/r2B) |E| = kq/A2C) |E| = kq/(r-A)2D) |E| = 0E) None of theseAER15CT 27.19A negative point charge with charge +Q sits in the interior of a thick spherical (conducting) metal shell (which carries +2 net charge).A: -QB: +QC: +2QD: -2QE: 0-QInnersurfaceOutersurfaceWhat is the total charge on the inner surface of the shell?ER16+2QCT 27.19bER17CT 27.19A negative point charge with charge +Q sits in the interior of a thick spherical (conducting) metal shell (which carries +2 net charge).A: -QB: +QC: +2QD: -2QE: 0-QInnersurfaceOutersurfaceWhat is the total charge on the outer surface of the shell?+2QThe electric field of a charge is defined by the force onA. an electron.B. a proton.C. a source charge.D.a test charge.ER18A piece of plastic is uniformly charged with surface charge density 1. The plastic is then broken into a large piece with surface charge density 2and a small piece with surface charge density 3. Rank in order, from largest to smallest, the surface charge densities 1to 3.A. η1> η2 > η3B. η1> η2 = η3C. η1= η2 = η3D. η2= η3 > η1E. η3> η2 > η1ER19Which of the following actions will increase the electric field strength at the position of the dot?A. Make the rod longer without changing the charge. B. Make the rod shorter without changing the charge. C. Make the rod fatter without changing the charge. D.Make the rod narrower without changing the charge. E. Remove charge from the rod.ER20This box containsA. a net positive charge.B. no net charge. C. a net negative charge.D.a positive charge. E. a negative charge. ER21The total electric flux through this box isA. 0 Nm2/C.B. 1 Nm2/C.C. 2 Nm2/C.D.4 Nm2/C.E. 6 Nm2/C.ER22Which Gaussian surface would allow you to easily use Gauss’s law to determine the electric field outside a uniformly charged cube?A. A sphere whose center coincides with the center of the charged cube.B. A cube whose center coincides with the center of the charged cube and which has parallel faces.C. Either A or B.D.Neither A nor


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CU-Boulder PHYS 1120 - Eng Physics 2, Exam I Review

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