Slide 1The Electric Field – W1D3Coulomb & vectorsSlide 4note for your edificationSlide 6Slide 7discussionThe Electric Fieldthe e field= F/QThe Electric FieldW1 D3More on Chapter 14New Groups are posted on our website.The Electric Field – W1D3No QUIZ today. First quiz next FridayCLICKERS: MONDAY STARTLast TimeCoulombs' LawVector Notation: <a,b,c>SuperpositionSymmetryToday – The concept of the Electric FieldPossibly some discussion about the electric dipoleNext Major Topic: Charge and MatterNote: There is a NEW WebAssign that will appear sometime today. Topic: E-FieldCOULOMB & VECTORS1 2202 11(Unit Vector in the ( )direction)4q qpe= �-2 1F r - rr runit=rrr( )unit=2 12 12 1r - rr - rr - rIn the figure, what are the horizontal and vertical components of the resultant electrostatic force on the charge in the lower left corner of the square if q = 1.5 x 10-7 C and a = 4.0 cm? (Assume the positive directions are upward and to the right.)132r1r3r2xy,0,0, ,00, ,0aa aa=<- >=<- - >=< - >123rrr2 2 2 2( ) ( ) (0) 2 2aa a a a== - + - + = =1 3r = rr2Note that r goes from the origin to the point where we are computingthe force. For our example, r=0.NOTE FOR YOUR EDIFICATIONun itrr =rLET’S DO IT!,0,0, , 00, , 0aa aa=<- >=<- - >=< - >123rrr2 2 2 2( ) ( ) (0) 2 2aa a a a== - + - + = =1 3r = rr21 2 32 2 201 2 321 2 32 2 201 2 32 23 31 2 1 23 3 3 3 330 01 2 32 2 2 244 2242 24 2 4 24 42 2unit unit unitunit unit unitx q q qqr r rqr r rq qr r r a aapepepe pe- - -- - -� �- -= + +� �� �� �� �- -= + +� �� �� �� �� �- - - -= + + = + +� �� �� �� �� �r r rFr r rr rr r r r`1 2 32 2 201 2 321 2 32 2 201 2 32 23 31 2 1 23 3 3 3 330 01 2 32302242242 22 24 42 222 ,0, 0 ,4unit unit unitunit unit unitq q qqr r rqr r rq qr r r a aaqa aapepepe pepe- - -- - -� �- -= + +� �� �� �� �- -= + +� �� �� �� �� �- - - -= + + = + +� �� �� �� �� �= - <- >- <- -r r rFr r rr rr r r r230220,0 0, ,02 222 ,0,0 , ,0 0, ,042 22 12, 0,0 1, ,0 0, 1,0 0.6, 0.16,042 2aaq aa a aaqNEWTONSapepe� �>+< - >� �� �� �= < >+< >+< - >� �� �� �= < >+< >+< - > =< - >� �� �,0,0, ,00, ,0aa aa=<- >=<- - >=< - >123rrrDISCUSSIONA proton is placed a distance d above a table and is then released.Describe its motion. The room is in a vacuum.d dObserved“wt_?”THE ELECTRIC FIELDqq==F EFETHE E FIELD= F/Q1 1E(r)DISCUSSIONIs the field
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