Chemistry 122 Winter 2005 Oregon State UniversityExam 2 February 24, 2005 Dr. Richard NafshunDO NOT OPEN THIS EXAM UNTIL INSTRUCTED.CALCULATORS ARE NOT TO BE SHARED.Test Form 3Instructions: You should have with you several number two pencils, an eraser, your 3" x 5" note card, a calculator, and your University ID Card. If you have notes with you, place them in a sealed backpack and place the backpack OUT OF SIGHT or place the notes directly on the table at the front of the room. Fill in the front page of the Scantron answer sheet with your test form number (listed above), last name, first name, middle initial, and student identification number. Leave the class section number blank.This exam consists of 25 multiple-choice questions. Each question has four points associated with it. Select the best multiple-choice answer by filling in the corresponding circle on the rear page of the answer sheet. If you have any questions before the exam, please ask. If you have any questions during the exam, please ask the proctor. Open and start this exam when instructed. When finished, place your Scantron form and note card in the appropriate stacks. You may keep the exam packet, so please show your work and mark the answers you selected on it.R = 0.0821 L•atm/mol•K 760 mm Hg = 760 torr = 1 atmkf (H2O) = 1.86 ºC/m M = mol/Lm = mol/kg1. The phase diagram below is for:(A) H2O.(B) CO2. 2. Consider the phase diagram below for compound Z-26. The normal boiling point is:(A) 0 ºC.(B) 30 ºC(C) 50 ºC(D) 100 ºC3. Lithium fluoride melts at 848 ºC. Lithium oxide melts at 1570 ºC. The difference in melting points can be attributed to:(A) Different intermolecular forces (dispersion, dipole-dipole, hydrogen bonding).(B) Different ionic charges (q+, q-).(C) Different distances between nuclei (d).(D) The sheet-like structure.(E) Network covalent compounds.4. Which of the following is false?(A) Carbon dioxide is a non-polar molecule.(B) Cesium oxide is a non-polar molecule.(C) Water is a polar molecule which exhibits hydrogen bonding.(D) Quartz is a network covalent compound.(E) Network covalent compounds typically melt at higher temperatures than molecules.5. The reaction below will produce: O O || || HOCH2OH + HOCCH2CH2CH2COH →(A) an ionic solid.(B) a polyester.(C) a network covalent compound.(D) quartz.(E) graphite.6. Which of the following compounds cannot undergo free radical polymerization?(A) CF2CF2(B) CCl2CCl2(C) CH2CH2(D)(E) CH2ClCH2Cl7. Which is not a polymer?(A) polyethylene(B) polypropylene(C) polystyrene(D) polynomials8. Consider CH3CH2OH. The intermolecular forces present in CH3CH2OH are:(A) dispersion forces only.(B) dispersion forces and dipole-dipole forces.(C) dispersion forces, dipole-dipole forces, and hydrogen bonding.(D) hydrogen bonding only.(E) network covalent.C CH HH9. Which of the following has a hydrophilic end (polar, water-loving end) and a hydrophobic end (non-polar, water-fearing end)?(A) methane (CH4).(B) soap.(C) lithium chloride.(D) helium.(E) diamond.10. The equivalent number of atoms in the BCC unit cell is:(A) 1.(B) 2.(C) 3.(D) 4.(E) 6.11. The structure below [from Worksheet 6 During Recitation] represents:(A) an SC unit cell.(B) a BCC unit cell.(C) a FCC unit cell.(D) a FBC unit cell.(E) an MTV unit cell.12. The freezing point of 5.00m aqueous MgCl2 is:(A) 118.6 C.(B) -9.30 C.(C) 18.6 C.(D) -18.6 C.(E) -27.9 C.13. A student dissolves 15.000 g of an unknown protein in 1200 mL of water at 308 K. She measures the osmotic pressure to be 0.0412 mm Hg. What is the molar mass of the protein?(A) 2.57 x 10-6 g/mol.(B) 5.83 x 106 g/mol.(C) 3.64 x 10-5 g/mol.(D) 8.44 x 106 g/mol.(E) 8.44 x 10-6 g/mol.14. Which of the following sets of compounds are expected to be soluble in water?(A) CH4, CO2, CF4(B) NaCl, CH4, CH3OCH3(C) NaCl, CH3CH2OH, NH3(D) NaCl, CCl4, C4H1015. Which has a higher boiling point, He or Kr? Why?(A) He has a higher boiling point because it has weaker dispersion forces than Kr.(B) He has a higher boiling point because it has stronger dispersion forces than Kr.(C) Kr has a higher boiling point because it has weaker dispersion forces than He.(D) Kr has a higher boiling point because it has stronger dispersion forces than He.16. A student places 14.00 grams of lithium fluoride into 400 g of water. Determine the molality of the solution.(A) 35.0 m(B) 0.0350 m(C) 2.86 m(D) 1.35 m(E) 0.741 m17. Why is molality used as the unit of concentration rather than molarity for colligative property calculations?(A) Molarity is not temperature dependent; molality is(B) Molality is not temperature dependent; molarity is.(C) Molality calculations are easier to perform in lab.(D) Molarity can only be used with network covalent compounds.(E) Molarity can only be used with hydrophobic molecules.18. The half-life is:(A) the amount of time required for the entire sample to decay.(B) 0.5 years.(C) the amount of time required for half the sample to decay.(D) the amount of time required for the sample to decay so that only a few atoms or molecules remain.19. A student ( ) obtains a 10.0 gram sample of 131I (t1/2 = 8.0 days). How many grams of 131I will remain after 16.0 days?(A) 2.5 grams(B) 5.0 grams(C) 10.0 grams(D) 20.0 grams(E) 80.0 grams20. A student ( ) obtains a 10.0 gram sample of 131I (t1/2 = 8.0 days). How long will it take so that only 3.0 grams of 131I remain?(A) 13.9 days(B) 14.7 days(C) 2.40 days(D) 1.52 days(E) 15.2 days21. Compounds with relatively high vapor pressure have:(A) high boiling points and weak intermolecular forces(B) low boiling points and weak intermolecular forces(C) high boiling points and strong intermolecular forces(D) high boiling points and strong intermolecular forces22. The data below were obtained for ethyl acetate. Estimate by interpolation the temperature when the vapor pressure is 918 torr.(A) 91.8 ºC.(B) 81 ºC.(C) 82 ºC.(D) 83 ºC.(E) 84 ºC.23. Consider carbon dioxide, sodium chloride, water, calcium oxide, and helium. Arranged in increasing melting point, these are:Lowest mp Highest mp(A) helium < sodium chloride < carbon dioxide < water < calcium oxide.(B) helium < sodium chloride < carbon dioxide < calcium oxide < water.(C) helium < carbon dioxide < water < sodium chloride < calcium oxide.(D) carbon dioxide < calcium oxide < water < helium < sodium chloride.(E) helium < carbon