Chemistry 121 Oregon State UniversityMole Exercise Notes Dr. Richard L Nafshun1 dozen = 12 1 mole = 6.022 x 10231. A student obtains 12.011 grams of carbon. How many moles of carbon are present? How many carbon atoms are present?12.011 g C Cg011.12mole1 = 1.0000 mol C1.0000 mol C Cmol1atomsC10x022.623 = 6.022 x 1023 C atoms2. A student obtains 24.022 grams of carbon. How many moles of carbon are present? How many carbon atoms are present?24.022 g C Cg011.12mole1 = 2.0000 mol C2.0000 mol C Cmol1atomsC10x022.623 = 1.204 x 1024 C atoms3. A student obtains 18.015 grams of water. How many moles of water are present? How many water molecules are present? How many oxygen atoms are present? How many hydrogen atoms are present?The Molar Mass (AKA Molecular Weight, AKA MM, AKA MWT) is 18.015 g/mol from the following:One oxygen atom = 15.9994 g/molOne hydrogen atom = 1.0079 g/molOne hydrogen atom = 1.0079 g/mol_________________________________________H2O = 18.015 g/mol18.015 g H2O OHg015.18mole12 = 1.0000 mol H2O1.0000 mol H2O OHmol1moleculesOH10x022.62223 = 6.022 x 1023 H2O molecules6.022 x 1023 H2O molecules moleculeOH1atomoxygen12 = 6.022 x 1023 O atoms6.022 x 1023 H2O molecules moleculeOH1atomshydrogen22 = 1.204 x 1024 H atoms4. A student obtains 32.04 grams of methanol, CH3OH. How many moles of methanol are present?The Molar Mass (AKA Molecular Weight, AKA MM, AKA MWT) is 32.04 g/mol from the following:One carbon atom = 12.01 g/molOne oxygen atom = 16.00 g/molFour hydrogen atoms = 4 * 1.0079 g/mol_________________________________________CH3OH = 32.04 g/mol32.04 g CH3OH OHCHg04.32mole13 = 1.0000 mol CH3OH5. A student obtains 100.00 grams of methanol, CH3OH. How many moles of methanol are present? How many methanol molecules are present? How many carbon atoms are present? How many hydrogen atoms are present? How many oxygen atoms are present?100.00 g CH3OH OHCHg04.32mole13 = 3.121 mol CH3OH3.121 mol CH3OH OHHCmol1moleculesOHHC10x022.63323 = 1.880 x 1024 CH3OH molecules1.880 x 1024 CH3OH molecules moleculeOHCH1atomcarbon13 = 1.880 x 1024 C atoms1.880 x 1024 CH3OH molecules moleculeOHCH1atomoxygen13 = 1.880 x 1024 O atoms1.880 x 1024 CH3OH molecules moleculeOHCH1atomshydrogen43 = 7.520 x 1024 H