1 CHAPTER 23 ELECTRIC POTENTIAL BASIC CONCEPTS: ELECTRIC POTENTIAL ENERGY ELECTRIC POTENTIAL ELECTRIC POTENTIAL GRADIENT – POTENTIAL DIFFERENCE 2 POTENTIAL ENERGY h PE = U = mgh PE KE Or U K And U + K = total energy = constant 3 BOOK EXAMPLE 4 Charged Particle in Electric Field is similar 5 Consider a point charge q that sets up an electric field in space 6 Now a test charge q0 is placed at position a a distance ra from q0. Then q0 moves to position b a distance rb from q0. What is the change in potential energy? The change in potential energy is the negative of the work done to move the test charge from a to b. The force on the test charge is 7 The work done is force times distance. But the force changes as q0 moves away from q Must integrate Use Then 8 The change in potential energy, is the negative of this work. DEFINITION: ELECTRICAL POTENTIAL IS POTENTIAL ENERGY PER UNIT CHARGE 9 Therefore divide all terms by Thus 10 Now consider the same situation 11 We have as we did at the beginning The change in potential energy, is the negative of this work. Therefore In Chapter 21 we defined the Electric Field as the force per unit charge 12 And we have Divide all terms by q0 13 POTENTIAL AT A POINT Once again look at this situation We have 14 Just like in potential energy of the particle on a hill we can choose the potential energy and therefore the potential to be zero at any arbitrary point. Choose infinity In the figure When 15 Then From Chapter 21 Therefore 16 Choose where 17 The potential at any point in space a distance from a charge will be POTENTIALS ADD (SCALERS) Just as we did with the electric field we can add the potentials for many charges in an area. 18 EXAMPLE A 60cm 30cm 50µC ‐50 µC What is the potential at A? 19 Example 23.11 Potential on axis of ring of charge. Choose small segment of ring that has charge . The segment is a distance form point P. Then 20 Integrate to get V Everything is constant except 21 Use the result to find potential on axis of disk of charge. This is diagram for E but use it for finding potential at P For ring of radius contribution to V is 22 Disk is made up of rings each with area Charge density of disk is total charge divided by total area Therefore 23 Integrate 24 For the disk 25 TWO MORE BASIC PIECES OF INFORMATION If we know V we can find E 26 Example In this chapter we found for ring of charge In chapter 21 we found for ring of charge Use equation above for V to find 27 28 ELECTRON VOLT An electron volt is a unit for energy. It is the work necessary to move an electron (charge ) a potential difference of 1 volt. 1 Volt Batt The work to move a charge across a potential difference is 29 Therefore
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