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NCSU MA 242 - Section 13.6

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Section 13.6 (Homework)Ali Al ZaabiMA 242, section 001, Spring 2012Instructor: J. Louis CappsCurrent Score : 21 / 21 Due : Monday, April 30 2012 11:06 PM EDT1. 3/3 points | Previous AnswersEvaluate the surface integral.S is the triangular region with vertices (1,0,0), (0,2,0), and (0,0,2) 0.408 0.4082. 3/3 points | Previous AnswersEvaluate the surface integral.S is part of the paraboloid x = 4 - y2- z2that lies in front of the plane x = 0 84.5 84.53. 3/3 points | Previous AnswersEvaluate the surface integral.S is the boundary of the region enclosed by the cylinder x2+ z2= 1 and the planes y = 0 and x + y = 2 -7.39 -7.394. 3/3 points | Previous AnswersEvaluate the surface integral.S is the part of the sphere x2+ y2+ z2= 1 that lies above the cone 0 05. 3/3 points | Previous AnswersEvaluate the surface integral SF·dS for the given vector field F and the oriented surface S. In other words, find the flux of F across S. Use the positive (outward) orientation.F(x,y,z) = x i + y j + z4kS is the part of the cone beneath the plane z = 1 with downward orientation1.05 1.056. 3/3 points | Previous AnswersEvaluate the surface integral SF·dS for the given vector field F and the oriented surface S. In other words, find the flux of F across S. Use the positive (outward) orientation.F(x,y,z) = -y i + x j + 3z kS is the hemisphere with upward orientation402 402WebAssignThe due date for this assignment is past. Your work can be viewed below, but no changes can be made.7. 3/3 points | Previous AnswersThe temperature at a point in a ball with conductivity K is inversely proportional to the distance from the center of the ball. Find the rate of heat flow across a sphere S of radius a with center at the center of the ball.12.6 12.6


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NCSU MA 242 - Section 13.6

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