DOC PREVIEW
GVSU EGR 365 - EGR365 Hydrostatic Forces

This preview shows page 1-2 out of 6 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 6 pages.
Access to all documents
Download any document
Ad free experience
View full document
Premium Document
Do you want full access? Go Premium and unlock all 6 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 6 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

Hydrostatic ForcesbyDan SchwarzSchool of EngineeringGrand Valley State UniversityEGR 365 – Fluid MechanicsSection 01Instructor: Dr. S. FleischmannMay 22, 2006OutlineI. Purpose StatementA. Experimentally determine the hydrostatic forces on a submerged planar surface.B. Compare experimental results to theoretical predictions.II. BackgroundA. The pressure variations within a volume of fluid can be described by Euler’s equation.pga (1)B. From Euler’s equation it was determined that pressure varies linearly in a static body of water open to the atmosphere. gzpzpatm(2)C. In this experiment an inclined, hinged door will be subjected to a hydrostatic load untilit opens. The experimental device is shown below. D. Two opposing moment equations were developed to determine when the door would open. (Details in appendix)1. Closing moments (gravity & string tension).   12sin'5.0sinmgLRTM (3)2. Opening moment (hydrostatic force of rising water)    1212cos3/cos/5.0dLgwdM (4)3. These two equations were set equal to each other to predict water depth as a function of tension. (depth was predicted by finding the roots of the resulting polynomial)E. Experimental Method.1. Measure all dimensions and angles shown in the figure with a ruler (mm) and protractor (degrees).2. Measure a mass (kg), record the measurement, and hang it from the pulley.3. Place a strip of tape on the side of the tank.4. Slowly fill the tank with water and mark the water level when it reaches the bottom of the door.5. Continue filling the tank with water and mark the water level as soon as the door opens.6. Measure the difference between the initial mark and the final mark and record the measurement.7. Repeat this method for several masses.III. Results / DiscussionA. The measurements taken from the experimental procedure are compared with the predicted water levels in the table below. Discrepancies were initially high because the water levels did not change much before the door opened.Mass (kg)Tension(N)Predicted WaterLevel (m)Measured WaterLevel (m)%Discrepancy0.0200 0.1962 0.0215 0.0420 95.62%0.0500 0.4905 0.0276 0.0460 66.91%0.1000 0.9810 0.0357 0.0530 48.67%0.2000 1.9620 0.0484 0.0630 30.30%0.5000 4.9050 0.0765 0.0910 19.00%0.7000 6.8670 0.0919 0.1040 13.23%B. Water depth was plotted as a function of tension in the figure below. The figure seemsto indicate that the predicted depths were less than the measured depths by the same amount. There may have been more moments and forces that where unaccounted for in the prediction.IV. ConclusionsA. Discrepancies were most likely caused by measurement error when measuring the water depth. (meniscus, reaction time, etc.)B. Discrepancies may also result from forces not accounted for in the equations such as friction in the hinges. V. AppendicesA. Appendix A – Derive Working Equations.1. Closing Moment Equationa. Determine moment caused by the weight acting on the centroid of the door. 1sin'5.0mgLb. Determine moment caused by the tension force on the door. 2sinRTc. Sum the closing moments.   12sin'5.0sinmgLRTM (3)2. Opening Moment Equationa. Setup generic moment integral. rPdAMb. Write r in terms of the variable s.262sdssLdAyILyLrcxrc. Write P in terms of the variable s.  1cosgsP d. Write dA in terms of the variable s. wdsdA e. Substitute r, P, and dA into the integral. dsgwssdssLM12cos26f. Integrate with respect to s. 1332cos6621gwssLsMg. Substitute )cos(1ds and rearrange the results.    1212cos3/cos/5.0dLgwdM (4)B. Appendix B – Assigned Design Calculation.1. The tension needed to hold the door shut with the water level at the hinges was determined to be 14.3726 N (1.4651 kg) using the equation: 2774.03674.10811076.255223 ddTC. Appendix C – Assigned Design Questions.1. Loosening the hinge pins on the door would reduce the friction moment createdon the door. Since the hinge friction was not accounted for in the working equation, reducing the friction would decrease the % discrepancy. 2. The foam would eliminate premature leaking at the bottom of the door which would make it easier to determine the opening depth. It would also increase the opening depth because the foam produces a frictional force.3. 4 points are required to fit a third degree polynomial. Since we are modeling a cubic relationship, we should collect at least 4 data points.4. Recording the water depth electronically would be advantageous since the depth measurement is difficult to


View Full Document
Download EGR365 Hydrostatic Forces
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view EGR365 Hydrostatic Forces and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view EGR365 Hydrostatic Forces 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?