MA 154 Lesson 13 DelworthMA 154 Lesson 13 DelworthSection 7.2 Trigonometric Equations- In this lesson, we will be looking for angles that make the statement true in a given interval.- We may use n (an arbitrary integer) as in the previous lesson (for multi-angle expressions). However, we will not stop there. The numbers 0, 1, 2, 3,.... may be ‘plugged’ into the solution to find all angles in the given interval.- The final solutions will be a finite number of angles.Find the solutions of the equation that are in the interval [0, 2).sin 3x 41cot2 cot0 1tan 233xp� �- =-� �� �2 sin2t sin t 1 01n x-1 0123This is not a multi-angle equation. As in the first example, this is a multi-angle equation, so a table with nwill have to be used.Notice: This is a quadratic equation of the form22 1 0x x- - =. We will use factoring.MA 154 Lesson 13 DelworthSection 7.2 Trigonometric Equationscos2 2sin23s in t cos t 1sin x cos x cot x csc x2Notice: This equation has two different functions. Using an identity, you must convert to an equation with only one function.This equation will be different from the previous equations! Hint: Think of an equation that is an identity (always true).This is the most difficult equation of this lesson. We cannot use a Pythagorean Identity unless we use a ‘trick’. We will square both sides (after subtracting cos t). However squaring both sides of an equation can lead to ‘extraneous
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