Math quiz 5 Jonathan Abraham Asaadi Started: August 27, 2007 1:27 PMQuestions: 10 Finish Save All Help1. (Points: 1) Solve for x: 12x - 2 = 2x 1. x = 1/2 2. x = 2 3. x = 5 4. x = 1/5 5. x = -2 Save Answer 2. (Points: 1) The value of y that satisfies the below equation is: (y/3.2) = 14 1. y = 17.2 2. y = 0 3. y = 3.2 4. y = 44.8 5. y = -3.8 Save Answer 3. (Points: 1) If 2x + 2y = 0 and Page 1 of 5Assessment8/27/2007https://onlinelearning.tamu.edu/webct/urw/lc287457063031.tp288667884021/allViewAsse...2x - 2y = -4 then 1. x = 0, y = -2 2. x = 0, y = 2 3. x = -2, y = 2 4. x = -1, y = 1 5. x = 2, y = -2 Save Answer 4. (Points: 1) Solve for R: 1. 2. 3. 4. 5. Save Answer 5. (Points: 1) In the triangle shown below: Page 2 of 5Assessment8/27/2007https://onlinelearning.tamu.edu/webct/urw/lc287457063031.tp288667884021/allViewAsse...1. sin( ) = a / c 2. sin( ) = a / b 3. sin( ) = c / a 4. sin( ) = b / c 5. sin( ) = c / b Save Answer 6. (Points: 1) In the diagram below, = 30o. That means: Page 3 of 5Assessment8/27/2007https://onlinelearning.tamu.edu/webct/urw/lc287457063031.tp288667884021/allViewAsse...1. = 45o 2. = 60o 3. = 30o 4. = 90o 5. = 120o Save Answer 7. (Points: 1) x2x= 1. x3 2. x-1 3. x2 4. x 5. x(1/2) Save Answer 8. (Points: 1) What is (4/5) * (5/10)? (where "*" designates multiplication) 1. 4/5 2. 14/10 3. 9/15 4. 2/5 5. 40/25 Save Answer Page 4 of 5Assessment8/27/2007https://onlinelearning.tamu.edu/webct/urw/lc287457063031.tp288667884021/allViewAsse...9. (Points: 1) If Alice is half as heavy as Bob and Bob is three times heavier than his Cat then 1. Alice is 0.67 times the weight of the Cat 2. Alice is 1.5 times the weight of the Cat 3. Alice is 6 times heavier than the Cat 4. Alice is 0.16 times the weight of the Cat 5. There is not enough information to determine a relationship between Alice's weight and theCat's Save Answer 10. (Points: 1) If then: 1. 2. 3. 4. 5. Save Answer Finish Save All HelpPage 5 of
View Full Document
Unlocking...