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PHYS 1111: Exam 2

Linear Work 
W=Fd W=Fdcosθ
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Work Energy Theorem 
Wtotal=delta K=1/2mvf^2-(1/2mvi^2)
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Power 
P=W/t P=Fv
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Potential energy 
gravitational: U=mgy Spring: U=1/2kx^2
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Total Mechanical Energy 
E=U+K
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Total work 
Wtotal=delta K Wtotal=W(c)+W(nc)
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Linear momentum 
p=mv
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Force 
F=ma F=p/t
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Moment of Inertia 
I=Ft I-delta (p)
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Inelastic collision 
Vf=(m1v1)+(m2v2)/m1+m2
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Elastic collision final velocity 
V1f=(m1-m2)/(m1+m2)*Vo V2f= (2mi)/(m1+m2)*Vo
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Center of Mass 
X=(m1x1)+(m2x2).../(M total) 
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Velocity of center of mass 
=(m1v1)+(m2v2)+..../M total
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Horsepower--> watts 
1 hp=746 watts 
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Acceleration of center of mass 
(m1a1)+(m2a1)/Mtotal
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Arc length 
S=rθ
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Angular velocity 
w=delta θ/delta t (rad/s)
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Period 
T=2Pi/w (s)
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Angular acceleration 
=delta w/delta t (rad/s^2)
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Tangential speed 
Vt=rw
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Tangential acceleration 
at=r(angular accel) 
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Rotational kinetic energy 
K=(1/2)Iw^2
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Kinetic energy of rolling motion
K=(1/2)mv^2+(1/2)Iw^2 OR =(1/2)mv^2+(1/2)(1+I/mr^2)
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Torque 
T=rF T=r(Fsinθ) T=I(angular accel) T= L2-L1/delta t T= w/delta θ T=delta L/delta t
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Angular momentum 
L=Iw L=rp L=rpsinθ (kg m^2/s)
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Centripetal acceleration  
acp=rw^2
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Work done by Torque 
W=Tdeltaθ
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