PHYS 1111: Exam 2
27 Cards in this Set
| Front | Back |
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Linear Work
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W=Fd
W=Fdcosθ
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Work Energy Theorem
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Wtotal=delta K=1/2mvf^2-(1/2mvi^2)
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Power
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P=W/t
P=Fv
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Potential energy
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gravitational: U=mgy
Spring: U=1/2kx^2
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Total Mechanical Energy
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E=U+K
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Total work
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Wtotal=delta K
Wtotal=W(c)+W(nc)
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Linear momentum
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p=mv
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Force
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F=ma
F=p/t
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Moment of Inertia
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I=Ft
I-delta (p)
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Inelastic collision
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Vf=(m1v1)+(m2v2)/m1+m2
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Elastic collision final velocity
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V1f=(m1-m2)/(m1+m2)*Vo
V2f= (2mi)/(m1+m2)*Vo
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Center of Mass
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X=(m1x1)+(m2x2).../(M total)
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Velocity of center of mass
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=(m1v1)+(m2v2)+..../M total
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Horsepower--> watts
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1 hp=746 watts
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Acceleration of center of mass
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(m1a1)+(m2a1)/Mtotal
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Arc length
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S=rθ
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Angular velocity
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w=delta θ/delta t
(rad/s)
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Period
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T=2Pi/w
(s)
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Angular acceleration
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=delta w/delta t
(rad/s^2)
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Tangential speed
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Vt=rw
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Tangential acceleration
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at=r(angular accel)
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Rotational kinetic energy
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K=(1/2)Iw^2
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Kinetic energy of rolling motion
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K=(1/2)mv^2+(1/2)Iw^2
OR
=(1/2)mv^2+(1/2)(1+I/mr^2)
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Torque
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T=rF
T=r(Fsinθ)
T=I(angular accel)
T= L2-L1/delta t
T= w/delta θ
T=delta L/delta t
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Angular momentum
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L=Iw
L=rp
L=rpsinθ
(kg m^2/s)
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Centripetal acceleration
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acp=rw^2
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Work done by Torque
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W=Tdeltaθ
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PHYS 1111: Common Prefixes