DOC PREVIEW
MIT 8 02 - Lecture Notes

This preview shows page 1-2-23-24 out of 24 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience
View full document
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience
View full document
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience
View full document
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 24 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

1P25-Class 25: Outline Hour 1: Expt. 10: Part I: Measuring L LC Circuits Hour 2: Expt. 10: Part II: LRC Circuit2P25-Last Time: Self Inductance3P25-Self InductanceLNI=Φ1. Assume a current I is flowing in your device2. Calculate the B field due to that I3. Calculate the flux due to that B field4. Calculate the self inductance (divide out I)dILdtε≡ −To Calculate:The Effect: Back EMF:Inductors hate change, like steady stateThey are the opposite of capacitors4P25-LR Circuitt=0+: Current is trying to change. Inductor works as hard as it needs to to stop itt=∞: Current is steady. Inductor does nothing.()/() 1tIt eRτε−=−5P25-LR Circuit: AC Output Voltage 0.00 0.01 0.02 0.03 0.00 0.05 0.10 0.15 0 1 2 3 ) ) Current -3 -2 -1 0 1 2 3 VollI (ATime (sInductor (V)tmeter across L Output (V) Output Vo tage6P25-Non-Ideal Inductors Non-Ideal (Real) Inductor: Not only L but also some R In direction of current: dIL IRdtε= −− =7P25-LR Circuit w/ Real Inductor Due to Resistance 1. Time constant from I or V 2. Check inductor resistance from V just before switch8P25-Experiment 10: Part I: Measure L, R STOP after you do Part I of Experiment 10 (through page E10-5)9P25-LC Circuits Mass on a Spring: Simple Harmonic Motion (Demonstration)10P25-Mass on a Spring22220dxFkxmamdtdxmkxdt=− = =+=00() cos( )xt x tωφ=+(1)(2)(3)(4)What is Motion?0Angular frequencykmω==Simple Harmonic Motionx0: Amplitude of Motionφ: Phase (time offset)11P25-Mass on a Spring: Energy00() cos( )xt x tωφ=+(1) Spring (2) Mass(3) Spring(4) MassEnergy has 2 parts: (Mass) Kinetic and (Spring) Potential222002220011sin ( )2211cos ( )22sdxKm kx tdtUkxkx tωφωφ⎛⎞== +⎜⎟⎝⎠== +00 0'( ) sin( )xt x tωωφ=− +Energy sloshes back and forth12P25-Simple Harmonic MotionAmplitude (x0)00() cos( )xt x tωφ=−1Period ( )frequency ( )2angular frequency ( )Tfπω==Phase Shift ( )2πϕ=13P25-Electronic Analog: LC Circuits14P25-Analog: LC CircuitMass doesn’t like to accelerateKinetic energy associated with motionInductor doesn’t like to have current changeEnergy associated with current2221;2dv d xFma m m E mvdt dt== = =2221;2dI d qLLELIdt dtε=− =− =15P25-Analog: LC CircuitSpring doesn’t like to be compressed/extendedPotential energy associated with compressionCapacitor doesn’t like to be charged (+ or -)Energy associated with stored charge21;2Fkx E kx=− =2111;2qE qCCε==1;;; ;FxqvImLkCε−→→→ →→16P25-LC Circuit resistor, and battery. 1. Set up the circuit above with capacitor, inductor, 2. Let the capacitor become fully charged. 3. Throw the switch from a to b 4. What happens?17P25-LC Circuit It undergoes simple harmonic motion, just like a mass on a spring, with trade-off between charge on capacitor (Spring) and current in inductor (Mass)18P25-PRS Questions: LC Circuit19P25-LC Circuit0 ; QdI dQLICdt dt−= =−2210 dQQdt LC+=00() cos( )Qt Q tωφ=+01LCω=Q0: Amplitude of Charge Oscillationφ: Phase (time offset)Simple Harmonic Motion20P25-LC Oscillations: Energy2220122 2EBQQUU U LICC=+= + =22200cos22EQQUtCCω⎛⎞==⎜⎟⎝⎠2222 2000 011sin sin22 2BQULILI t tCωω⎛⎞== =⎜⎟⎝⎠Total energy is conserved !!Notice relative phases21P25-Adding Damping: RLC Circuits22P25-Damped LC Oscillations Resistor dissipates energy and system rings down over time Also, frequency decreases: 2 2 0 ' 2 R Lω ω ⎛ ⎞ = −⎜ ⎟⎝ ⎠23P25-Experiment 10: Part II: RLC Circuit Use Units24P25-PRS Questions: 2 Lab


View Full Document

MIT 8 02 - Lecture Notes

Documents in this Course
Exam 2

Exam 2

1 pages

Exam 1

Exam 1

2 pages

Load more
Download Lecture Notes
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Lecture Notes and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Lecture Notes 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?