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Princeton COS 318 - Storage Devices

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COS 318: Operating Systems Storage Devices Kai Li Computer Science Department Princeton University (http://www.cs.princeton.edu/courses/cos318/)2 Today’s Topics  Magnetic disks  Magnetic disk performance  Disk arrays  Flash memory3 A Typical Magnetic Disk Controller  External connection  IDE/ATA, SATA  SCSI, SCSI-2, Ultra SCSI, Ultra-160 SCSI, Ultra-320 SCSI  Fibre channel  Cache  Buffer data between disk and interface  Controller  Read/write operation  Cache replacement  Failure detection and recovery DRAM cache Interface Controller External connection Disk4 Disk Caching  Method  Use DRAM to cache recently accessed blocks • Most disk has 16MB • Some of the RAM space stores “firmware” (an embedded OS)  Blocks are replaced usually in an LRU order  Pros  Good for reads if accesses have locality  Cons  Cost  Need to deal with reliable writesDisk Arm and Head  Disk arm  A disk arm carries disk heads  Disk head  Mounted on an actuator  Read and write on disk surface  Read/write operation  Disk controller receives a command with <track#, sector#>  Seek the right cylinder (tracks)  Wait until the right sector comes  Perform read/write6 Mechanical Component of A Disk Drive  Tracks  Concentric rings around disk surface, bits laid out serially along each track  Cylinder  A track of the platter, 1000-5000 cylinders per zone, 1 spare per zone  Sectors  Each track is split into arc of track (min unit of transfer)7 Disk Sectors  Where do they come from?  Formatting process  Logical maps to physical  What is a sector?  Header (ID, defect flag, …)  Real space (e.g. 512 bytes)  Trailer (ECC code)  What about errors?  Detect errors in a sector  Correct them with ECC  If not recoverable, replace it with a spare  Skip bad sectors in the future Hdr Sector … 512 bytes ECC i i+1 i+2 defect defect8 Disks Were Large First Disk: IBM 305 RAMAC (1956) 5MB capacity 50 disks, each 24”9 They Are Now Much Smaller Form factor: .5-1”× 4”× 5.7” Storage: 0.5-2TB Form factor: .4-.7” × 2.7” × 3.9” Storage: 60-200GB Form factor: .2-.4” × 2.1” × 3.4” Storage: 1GB-8GB10 Areal Density vs. Moore’s Law (Mark Kryder at SNW 2006)11 50 Years Later (Mark Kryder at SNW 2006) IBM RAMAC (1956) Seagate Momentus (2006) Difference Capacity 5MB 160GB 32,000 Areal Density 2K bits/in2 130 Gbits/in2 65,000,000 Disks 50 @ 24” diameter 2 @ 2.5” diameter 1 / 2,300 Price/MB $1,000 $0.01 1 / 3,200,000 Spindle Speed 1,200 RPM 5,400 RPM 5 Seek Time 600 ms 10 ms 1 / 60 Data Rate 10 KB/s 44 MB/s 4,400 Power 5000 W 2 W 1 / 2,500 Weight ~ 1 ton 4 oz 1 / 9,00012 Sample Disk Specs (from Seagate) Cheetah 15k.7 Barracuda XT Capacity Formatted capacity (GB) 600 2000 Discs 4 4 Heads 8 8 Sector size (bytes) 512 512 Performance External interface Ultra320 SCSI, FC, S. SCSI SATA Spindle speed (RPM) 15,000 7,200 Average latency (msec) 2.0 4.16 Seek time, read/write (ms) 3.5/3.9 8.5/9.5 Track-to-track read/write (ms) 0.2-0.4 0.8/1.0 Internal transfer (MB/sec) 1,450-2,370 600 Transfer rate (MB/sec) 122-204 138 Cache size (MB) 16 64 Reliability Recoverable read errors 1 per 1012 bits read 1 per 1010 bits read Non-recoverable read errors 1 per 1016 bits read 1 per 1014 bits readDisk Performance (2TB disk)  Seek  Position heads over cylinder, typically 3.5-9.5 ms  Rotational delay  Wait for a sector to rotate underneath the heads  Typically 8 - 4 ms (7,200 – 15,000RPM) or ½ rotation takes 4 - 2ms  Transfer bytes  Transfer bandwidth is typically 40-138 Mbytes/sec  Performance of transfer 1 Kbytes  Seek (4 ms) + half rotational delay (2ms) + transfer (0.013 ms)  Total time is 6.01 ms or 167 Kbytes/sec (1/360 of 60MB/sec)!14 More on Performance  What transfer size can get 90% of the disk bandwidth?  Assume Disk BW = 60MB/sec, ½ rotation = 2ms, ½ seek = 4ms  BW * 90% = size / (size/BW + rotation + seek)  size = BW * (rotation + seek) * 0.9 / 0.1 = 60MB * 0.006 * 0.9 / 0.1 = 3.24MB  Seek and rotational times dominate the cost of small accesses  Disk transfer bandwidth are wasted  Need algorithms to reduce seek time  Speed depends on which sectors to access  Are outer tracks or inner tracks faster? Block Size (Kbytes) % of Disk Transfer Bandwidth 1Kbytes 0.28% 1Mbytes 73.99% 3.24Mbytes 90%15 FIFO (FCFS) order  Method  First come first serve  Pros  Fairness among requests  In the order applications expect  Cons  Arrival may be on random spots on the disk (long seeks)  Wild swing can happen 0 199 98, 183, 37, 122, 14, 124, 65, 67 5316 SSTF (Shortest Seek Time First)  Method  Pick the one closest on disk  Rotational delay is in calculation  Pros  Try to minimize seek time  Cons  Starvation  Question  Is SSTF optimal?  Can we avoid the starvation? 0 199 98, 183, 37, 122, 14, 124, 65, 67 (65, 67, 37, 14, 98, 122, 124, 183) 5317 Elevator (SCAN)  Method  Take the closest request in the direction of travel  Real implementations do not go to the end (called LOOK)  Pros  Bounded time for each request  Cons  Request at the other end will take a while 0 199 98, 183, 37, 122, 14, 124, 65, 67 (37, 14, 65, 67, 98, 122, 124, 183) 5318 C-SCAN (Circular SCAN)  Method  Like SCAN  But, wrap around  Real implementation doesn’t go to the end (C-LOOK)  Pros  Uniform service time  Cons  Do nothing on the return 0 199 98, 183, 37, 122, 14, 124, 65, 67 (65, 67, 98, 122, 124, 183, 14, 37) 5319 Discussions  Which is your favorite?  FIFO  SSTF  SCAN  C-SCAN  Disk I/O request buffering  Where would you buffer requests?  How long would you buffer requests?20 RAID (Redundant Array of Independent Disks)  Main idea  Store the error correcting codes on other disks  General error correcting codes are too powerful  Use XORs or single parity  Upon any failure, one can


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Princeton COS 318 - Storage Devices

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