CHEM 1332 1st Edition Lecture 13 Outline of Last Lecture - Reaction quotient - Le Chatelier’s Principle- Finding Kc value- Reaction tableOutline of Current Lecture - Problem- Acids- Percent errorCurrent Lecture- If you are given the balanced equation H2+I2⇄2 HI and the problem mix 3 mol/LH2 and I2 and Kc and calculate equilibrium HI- We then need to setup the equation Kc=HI2eqH2eq I2eq- We then setup the reaction table for this one it is GeneralH2I22HIStart 3 3 0Change -x -x +2xEquilibrium 3-x 3-x 2x- The reactants are negative because we are assuming that they are being used up- Next plug in to what you know 49=2 x2(3−x )(3 −x)- Then we take the square root from both sides and we get 7=2 x3−x- We solve for x and get 7/3 or 2.333- HI then is equal to 2x=4.66 mol/L- Kc is in mol/L and it is for gases and solutions- Kp is in atm and it is for gases- Both excludes solids and liquidsThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.- Acids dissociate in water +¿H¿ and this is important about acid and anion - Strong acids are HCl, HBr, HI, HClO, HNO3, H2SO4- Strong acids dissociate by a hundred percent- Weak acids are HF, H3PO4, CH3COOH - Weak acids partially dissociate in water - This means that if there are a thousand molecules only a percentage will dissociate- Strong acids have a large Ka value- Weak acids have small Ka value- In certain equations we can make assumptions in the calculations if we do so we need tomake sure that this is does not truly affect the answer to check the percent error you take the answer over the assumption and multiply by a hundred if it is less than five percent this assumption is ok.Key TermsAcids- A substance that yields hydrogen ions when dissolved in waterPercent error- approximations are used instead of the real
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