The class NPThe HAMPATH problemPolynomial verifiabilityThe COMPOSITES problemDefinition of a verifierDefinition of NPNP in terms of nondeterministic Turing machinesDefinition of NTIME(t(n))The CLIQUE problemThe SUBSET-SUM problemP vs. NP vs. coNP vs. EXPTIMEThe class NPThe class NPSection 7.3 Giorgi Japaridze Theory of ComputabilityThe HAMPATH problem 7.3.aGiorgi Japaridze Theory of ComputabilityA Hamiltonian path in a directed graph G is a directed path that goes through each node exactly once. We consider a special case of this problem where the start nodeand target node are fixed.HAMPATH = {<G,s,t> | G is a directed graph with a Hamiltonian path from s to t} s 1 2 3 4 5 6 t s 1 2 3 4 5 6 t PATH? HAMPATH? HAMPATH?Polynomial verifiability 7.3.bGiorgi Japaridze Theory of Computability s tDoes this graph have aHamiltonian path?The COMPOSITES problem 7.3.cGiorgi Japaridze Theory of ComputabilityCOMPOSITES = {x | x=pq for some integers p,q>1}15  COMPOSITES ? 17  COMPOSITES ?77  COMPOSITES ?10403  COMPOSITES ?997,111,111,911,111,119,131,119,871  COMPOSITES ?COMPOSITES is very easily seen to be verifiable in polynomial time.But only a few years ago it was proven that it is also decidable in polynomial time. The same question, however, remains open forHAMPATH --- one of the seven $1,000,000 questions!Definition of a verifier7.3.dGiorgi Japaridze Theory of ComputabilityDefinition 7.18 A verifier for a language A is an algorithm V, where A = {w | V accepts <w,c> for some string c}.We measure the time of a verifier only in terms of the length of w, so a polynomial time verifier runs in polynomial time in the length of w. A language A is polynomially verifiable if it has a polynomial time verifier. The above string c, used as additional information to verify that wA, is called a certificate, or proof, of membership in A. What is a certificate for <G,s,t>  HAMPATH? What is a verifier for HAMPATH?Observe that, for polynomial verifiers, the certificate has polynomial length (in the length of w) because that is all the verifier can access in its time bound. What is a certificate for x  COMPOSITES? What is a verifier for COMPOSITES?Definition of NP7.3.eGiorgi Japaridze Theory of ComputabilityDefinition 7.19 NP is the class of languages that have polynomial time verifiers. A very important class, because many natural and important problems are in it! NP stand for “nondeterministic polynomial”. As it turns out (Theorem 7.20), an alternative characterization of NP is to say that this is the class of languages decidable by polynomial-time nondeterministic Turing machines. Here is such a machine for HAMPATH:N1 = “On input <G,s,t>, where G is a directed graph with nodes s and t: 1. Write a list on m members p1,…,pm, where m is the number of nodes of G. Each number in the list is nondeterministically selected to be between 1 and m. 2. Check for repetitions in the list. If any are found, reject. 3. Check whether s=p1 and t=pm. If either fail, reject. 4. For each i between 1 and m-1, check whether (pi,pi+1) is an edge of G. If any are not, reject. Otherwise, all tests have been passed, so accept.”NP in terms of nondeterministic Turing machines7.3.fGiorgi Japaridze Theory of ComputabilityTheorem 7.20 A language is in NP iff it is decided by some nondeterministic polynomial time Turing machine. Proof. The idea is to show how to convert a polynomial time verifier into a polynomial time NTM, and vice versa. The NTM simulates the verifier by guessing the certificate. The verifier simulates the NTM by using the accepting branch as the certificate.() Assume ANP. Let V be a verifier for A with VTIME(nk), which, by the definition of NP, exists. Construct N as follows: N = “On input w of length n: 1. Nondeterministically select a string c of length at most nk. 2. Run V on input <w,c>. 3. If V accepts, accept; otherwise reject.”() Assume A is decided by a polynomial time NTM N. Construct a verifier V as follows: V = “On input <w,c>, where w and c are strings: Check whether c is (encodes) an accepting computation branch of N on input w. If yes, accept; otherwise reject.”Definition of NTIME(t(n))7.3.gGiorgi Japaridze Theory of ComputabilityDefinition 7.21 Let t(n) be a function. NTIME(t(n)) is defined as {L | L is a language decided by some O(t(n)) time NTM}. Corollary 7.22 NP = NTIME(n1)  NTIME(n2)  NTIME(n3)  NTIME(n4)  …Just like P, the class NP is insensitive to the choice of the reasonableunderlying computational model because all such models are polynomially equivalent. So, when describing and analyzing nondeterministic polynomial algorithms, we can follow the preceding (lazy man’s) conventions for deterministic polynomial time algorithms.The CLIQUE problem7.3.hGiorgi Japaridze Theory of ComputabilityA k-clique in an undirected graph is a subgraph with k nodes, wherein every two nodes are connected by an edge. On the right we see a 5-clique CLIQUE = {<G,k> | G is an undirected graph with a k-clique}Theorem 7.24 CLIQUENP. Proof. Here is a polynomial time verifier V for CLIQUE:V = “On input <<G,k>,c>: 1. Test whether c is a set of k nodes in G. 2. Test whether G contains all edges connecting nodes in c. 3. If both pass, accept; otherwise reject.” Idea: The clique is the certificate.Alternative proof. Here is a polynomial time NTM N deciding CLIQUE:N = “On input <G,k>: 1. Nondeterministically select a subset c of k nodes of G. 2. Test whether G contains all edges connecting nodes in c. 3. If yes, accept; otherwise reject.”The SUBSET-SUM problem7.3.iGiorgi Japaridze Theory of ComputabilitySUBSET-SUM = {<S,t> | S is a multiset of integers and, for some RS, the sum of all elements of R equals t}Theorem 7.25 SUBSET-SUMNP. Proof. Here is a polynomial time verifier V for SUBSET-SUM:V = “On input <<S,t>,c>: 1. Test whether c is a collection of numbers that sum to t. 2. Test whether S contains all the numbers in c. 3. If both pass, accept; otherwise reject.” Idea: The subset is the certificate.Alternative proof. Here is a polynomial time NTM N deciding SUBSET-SUM:N = “On input <S,t>: 1. Nondeterministically select a subset c of S. 2. Test whether the elements of c sum up to t. 3. If yes, accept; otherwise reject.”P vs. NP vs. coNP vs. EXPTIME7.3.jGiorgi Japaridze Theory of