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UK PHY 213 - Lec-10 Strachan

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Physics 213 General PhysicsPowerPoint PresentationSlide 3Slide 4Torque on a Current Loop, The Standard ConventionSlide 6Slide 7MotorsSlide 9Slide 10Slide 11Reverse the current and field.Slide 13Magnetic Fields – Long Straight WireDirection of the Field of a Long Straight WireMagnitude of the Field of a Long Straight WireAmpère’s Law, and Field from CurrentsAmpère’s Law to Find B for a Long Straight WireMagnetic Force Between Two Parallel ConductorsMagnetic Force Between Two Parallel Conductors, DerivedForce Between Two Conductors, contSlide 22Slide 23Slide 24Slide 25Slide 26Slide 27Slide 28Slide 29Magnetic MaterialsDemoTypes of Magnetic MaterialsMagnetic Effects of Electrons – SpinsFerromagnetic DomainsSlide 35Slide 36Slide 37Slide 38Physics 213General PhysicsLecture 102Last Meeting: Lorentz Force and TorqueToday: Review Torque, Magnetic Field of Conductors and Currents, Ampere’s Law, Solenoid, and Magnetic Materials34θ┴θ*Important: This  is not the same as in the previous slide.is now the angle between the radius vector and the force vector. 5Torque on a Current Loop,The Standard Convention Applies to any shape loopN is the number of turns in the coil Torque has a maximum value of NBIAWhen  = 90°Torque is zero when the field is perpendicular to the plane of the loop6xˆyˆzˆIBsinBIANDetermining Magnetic Moments and Torques for a Current LoopDirections are always determined with right-hand rule.Magnitudes are given by7 ┴μ =μμθθ8Motors9μsin B Review10IxˆyˆzˆBxˆyˆzˆBxˆyˆzˆB(A)(B) (C) It will not rotate.11IxˆyˆzˆBxˆyˆzˆBxˆyˆzˆB(A)(B) (C) It will not rotate.12IxˆyˆzˆBxˆyˆzˆBxˆyˆzˆB(A)(B) (C) It will not rotate.Reverse the current and field.1. CW 2. CCW3. It will not rotatexˆyˆzˆBCCWReverse the current and field.Magnetic Fields – Long Straight WireA current-carrying wire produces a magnetic fieldThe compass needle deflects in directions tangent to the circleThe compass needle points in the direction of the magnetic field produced by the currentDirection of the Field of a Long Straight WireRight Hand RuleGrasp the wire in your right handPoint your thumb in the direction of the currentYour fingers will curl in the direction of the fieldMagnitude of the Field of a Long Straight WireThe magnitude of the field at a distance r from a wire carrying a current of I isµo = 4  x 10-7 T.m / Aµo is called the permeability of free space2oIBrAmpère’s Law, and Field from CurrentsChoose an arbitrary closed path around the currentSum all the products of B|| Δℓ around the closed pathB|| Δℓ = µo IAmpère’s Law to Find B for a Long Straight WireUse a closed circular pathThe circumference of the circle is 2  r This is identical to the result previously obtained2oIBrMagnetic Force Between Two Parallel ConductorsThe force on wire 1 is due to the current in wire 1 and the magnetic field produced by wire 2The force per unit length is:1 22oI IFdMagnetic Force Between Two Parallel Conductors, DerivedThe force on wire 1F1 = I1 B ℓ sin θ B produced by wire 2sin=1, so1 22oI IFddIB220Force Between Two Conductors, contParallel conductors carrying currents in the same direction attract each other Parallel conductors carrying currents in the opposite directions repel each otherDemo of two current-carrying wires attracting/repelling.2223Circular current loops act like Magnetics, with a N and S pole.242526270 0NB =μ NI B= Illm�2829Magnetic MaterialsDemoMagnetic materials.Types of Magnetic MaterialsFerromagneticPermanent magnetic moments. Repel or attract depending on orientationParamagneticInduced magnetism in same direction as applied field. Materials are attracted to magnets.DiamagneticInduced magnetism in opposite direction as applied field. Materials are repelled. S N S N S N S N S N S N NS S N S N NSMagnetic Effects of Electrons – Spins Electrons also have spinThe classical model is to consider the electrons to spin like topsIt is actually a quantum effectFerromagnetic DomainsRandom alignment (left) shows an unmagnetized materialWhen an external field is applied, the domains aligned with B grow (right)Each domain acts like a little magnet with a N and S pole. Arrows below represent the magnetic moment.NSA loop of wire with a weight of 1.47 N is oriented vertically and carries a current I = 1.75 A. A segment of the wire passes through a magnetic field directed into the plane of the page as shown. The net force on the wire is measured using a balance and found to be zero. What is the magnitude of the magnetic field?(a) zero tesla (d) 1.5 T(b) 0.51 T (e) 4.2 T(c) 0.84 TXThe magnetic force is pointing upwards and cancels the gravitational force:1.471.474.20(1.75 )(0.20 )B gF BIl F NNB TA m= = == =Two long, straight, parallel wires separated by a distance d carry currents in opposite directions as shown in the figure. The bottom wire carries a current of 6.0 A. Point C is at the midpoint between the wires and point O is a distance 0.50d below the 6-A wire as suggested in the figure. The total magnetic field at point O is zero tesla.1. Determine the value of the current, I, in the top wire.(a) 2 A (c) 6 A (e) This cannot be determined since(b) 3 A (d) 18 A the value of d is not specified.X2. Determine the magnitude of the magnetic field at point C if d = 0.10 m.(a) 2.4x10–5 T (c) 9.6x10–5 T (e) 1.4x10–4 T(b) 4.8x10–5 T (d) 1.1x10–4 TX0 01 2(6.0 ),2 (1.5 ) 2 (0.5 )3 (6.0 ) 18.0I AB Bd dI A Am mp p= = == � =07518.0 6.0( ) ( )2 0.5 0.5(4 10 / )(24.0 ) 2 0.05 9.60 10A AB outd dTm A AmTmppp--= +�=�=


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UK PHY 213 - Lec-10 Strachan

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