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EIU CIS 3700 - CIS 3700 Review For Exam 2

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Review For Exam 2IP SubnettingStructure of IP addressesReserved IP addressesSlide 5Network maskThe ADDing techniqueTwo Virtual LANsTwo interconnected LANsSubnetting a class C networkSlide 11Slide 12Question 1Question 2Disk ManagementBasic diskDynamic diskMirrored volumeRAID-5 volumeConverting Basic disk to Dynamic diskConverting Dynamic disk to Basic diskLimitations of Dynamic diskFile system securityShared FoldersShared Folder PermissionsNTFS PermissionsShares & permissionsExercise 1Exercise 1 (Cont.)Distributed File System, Disk QuotasDfs: Scenario 1Dfs: Scenario 2Dfs implementation in Win 2000Slide 34Disk Quotas1Review For Exam 2(Week 8, Monday 10/10/2005)© Abdou Illia, Fall 20052IP Subnetting3Structure of IP addressesNetwork Part (n)Local Part (h)Class A nnnnnnnn.hhhhhhhh.hhhhhhhh.hhhhhhhh 10.0.0.1 – 126.255.255.255Class B nnnnnnnn.nnnnnnnn.hhhhhhhh.hhhhhhhh 128.0.0.1 – 191.255.255.255Class C nnnnnnnn.nnnnnnnn.nnnnnnnn.hhhhhhhh 192.0.0.1 – 223.255.255.255Sgmt. part Host part4Reserved IP addressesClass RangeA 10.0.0.0 – 10.255.255.255B 172.16.0.0 – 172.31.255.255C 192.168.0.0 – 192.168.255.255IP addresses reserved for private use.Address Use255.255.255.255 local broadcast to LAN computersExample: 10.255.255.255 Directed broadcast to network 10.0.0.0/8127.0.0.1 Loopback address (for self addressing)0.0.0.0 ProhibitedSpecial IP addresses.5Structure of IP addressesThe division between Network part, Segment part, and Host part is determined by a computer or a router by using a network mask. Network PartSegmentPartHostPart6Network maskA 32 bit number, just like an IP address, where all bits in the Network Part and the Segment Part are set to 1, and all bits in the Host Part are set to 0 like:11111111 11111111 11111111 00000000 (or 255.255.255.0 in decimal notation)7The ADDing techniqueDo the following three Class C IP addresses belong to the same network? 192.168.1.1, 192.168.1.50 and 192.168.2.1IP: 11000000 10101000 00000001 00000001 192.168.1.1Mask: 11111111 11111111 11111111 00000000 255.255.255.0Network: 11000000 10101000 00000001 00000000 192.168.1.0/24IP: 11000000 10101000 00000001 00110010 192.168.1.50Mask: 11111111 11111111 11111111 00000000 255.255.255.0Network: 11000000 10101000 00000001 00000000 192.168.1.0/24IP: 11000000 10101000 00000010 00000001 192.168.2.1Mask: 11111111 11111111 11111111 00000000 255.255.255.0Network: 11000000 10101000 00000010 00000000 192.168.2.0/241286432168421Network 1: 192.168.1.0/24, i.e network starting at 192.168.1.0 with network mask 255.255.255.0.Network 2: 192.168.2.0/24, i.e network starting at 192.168.2.0 with network mask 255.255.255.0.8Two Virtual LANs192.168.1.1255.255.255.0192.168.1.2255.255.255.0192.168.1.3255.255.255.0192.168.2.1255.255.255.0192.168.2.2255.255.255.0192.168.2.3255.255.255.0Switch9Two interconnected LANs10Subnetting a class C networkSuppose the 192.168.1.0/24 networkYou want to divide that network into two segmentsYou can decide to use the first bit of the fourth octet as dividing point between your network segments. So, your network mask would be: 11111111 11111111 11111111 10000000 And you will have about 27 = 128 hosts in each segment.1286432168421Segment 1: 192.168.1.0 to 192.168.1.127 Segment 2: 192.168.1.128 to 192.168.1.255How to create the two segments using the ADDing technique?11Subnetting a class C networkIP: 11000000 10101000 00000001 00000001 192.168.1.1Mask: 11111111 11111111 11111111 10000000 255.255.255.128Network: 11000000 10101000 00000001 00000000 192.168.1.0/25. . . . . .. . . . . .. . . . . .. . . . . .IP: 11000000 10101000 00000001 01111111 192.168.1.127Mask: 11111111 11111111 11111111 10000000 255.255.255.128Network: 11000000 10101000 00000001 00000000 192.168.1.0/251286432168421Segment 1: 192.168.1.0 to 192.168.1.12712Subnetting a class C networkIP: 11000000 10101000 00000001 10000000 192.168.1.128Mask: 11111111 11111111 11111111 10000000 255.255.255.128Network: 11000000 10101000 00000001 10000000 192.168.1.128/25. . . . . .. . . . . .. . . . . .. . . . . .IP: 11000000 10101000 00000001 11111110 192.168.1.254Mask: 11111111 11111111 11111111 10000000 255.255.255.128Network: 11000000 10101000 00000001 10000000 192.168.1.128/251286432168421Segment 2: 192.168.1.128 to 192.168.1.25513Question 1Network A is IP network 192.168.2.0/24 (i.e a Class C network with a default 24-bit mask). Using the IP Subnet Calculator, determine the maximum number of hosts (computers) in each of the Network A’s subnets assuming that there are two subnets. You answer: ________.Using the IP Subnet Calculator, determine the maximum number of subnets for a Class B network assuming that the four first bits of the third octet in each IP address are used as subnet bits. Your answer: _____. What is the maximum number of computers for each subnet? Your answer: ______.14Question 2Consider the 192.168.2.0/24 network.What is the maximum number of hosts in that network?Suppose that the 192.168.2.0/24 network is segmented, and became 192.168.2.0/25What is the maximum number of hosts in in each subnet?Would IP address 192.168.2.1 be in the same subnet as IP address 192.168.2.126? Consider the 192.168.2.0/24 network. You want to segment that network in order to create 4 subnets.What would be the four (4) address ranges?What would your subnet mask be?15Disk Management16Basic diskA physical disk that can be accessed by MS-DOS and all Windows-based operating systems. Basic disks can contain up to 4 primary partitions, or 3 primary partitions and an extended partition with multiple logical drives. Primary partition 1Primary partition 2Primary partition 3Primary partition 4Primary partition 1Primary partition 2Primary partition 3Extended partition• A primary partition is a portion of a physical disk that functions as though it were a physically separate disk.• You create a primary partition, then you format it with a file system (FAT or NTFS,) and then assign a drive letter to it (e.g. C:, D:, F:, etc.)• A primary partition can start the OS (contain the boot files)• A special kind of partition used to create one or more logical drives• After you create a logical drive, you format it and assign it a drive letter (e.g. G:, H:, etc.)• An extended partition cannot start the OS.Note: With GPT (GUID partition table) disk-partitioning scheme that is used by the Extensible Firmware Interface (EFI) in Itanium-based computers, we can create up to 128 (primary)


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EIU CIS 3700 - CIS 3700 Review For Exam 2

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