Unformatted text preview:

March 30, 2004 1Pulse Doppler Radar Assume a target at a distance R and has a radial velocity component of Vr. The round-trip distance to target is 2R. This is equivalent to 2R/λ wavelengths or (2R/λ)2π = 4πR/λ radians. If the phase of the transmitted signal is φo, then the phase of the received signal is λπφφR40+= The change in phase between pulses is rVdtdRdtdλπλπφ44== . The left hand side of the equation is equal to the frequency 2πfd, so that λλππrdrdVfVf242 ==>= (1) Alternatively, let the transmitted frequency be ft. The received signal can be represented as ))(2sin(rec RtTtfKA −=π. The round-trip time TR is equal to 2R/c . With a radial velocity of Vr the round-trip time is changing as R = R0 – Vrt. Thus, the received signal is −+=cRftcVfKAtrt0rec4212sinππ Thus, the received frequency changes by a factor 2ftVr/c = 2Vr/λ., which is the same as before. The Nyquist criterion says that fmax = PRF/2, combining this with Equation (1), results in 4maxλPRFV = (2) This is the maximum unambiguous velocity. Higher velocities cause velocity folding or velocity aliases. Maximum unambiguous range is PRFcR2max= . This causes range folding or range aliases. Combining this with Equation (1) results in This summarizes the Doppler dilemma: a large Rmax implies a small Vmax and vice versa. 8maxmaxλcRV =March 30, 2004 2 Recognizing and dealing with range an velocity aliases. • Look outside. • Examine horizontal and vertical shapes of object. For example range-aliased storms become skinny close-by objects. Storm heights are suspicious – convective storms are 10–15 km tall. Aliased they would be say 2 km tall, which is unrealistic. • Examine reflectivities in conjunction with other factors, • Change PRF–real echoes will not change position, but aliases will. This is not alwas an option. • Velocity folding causes a change in sign, which is relatively easy to spot if the folding is within a larger region. • Watch out, one can get multiple velocity foldings. Example 1. A 3-cm radar with PRF of 1000 Hz is pointed towards a storm located 200 km from the radar. The radar display will show an alias at 200 km - c/(2PRF) = 50 km. The storm is moving away from the radar with a radial velocity of 25 miles per hour, or 11.1 m/s. The radar will display the storm velocity as (PRF×λ)/4 – 11.11 = 7.5-11.1 = 3.6 m/s towards the radar. Example 2. A scanning radar with a PRF of 1000 Hz observes two identical distributed targets located at R1 = 80 km and another at R2 = 210 km (see below). Sketch and dimension a PPI up to 200 km. Answer. The unambiguous range for the radar is c/(2PRF) = 150 km. The first target will not alias, the radar measures P1 and R1 and its processor outputs a reflectivity factorMarch 30, 2004 321131RPcz = . The radars measures a power P2 =P1(R1/R2)2 for the second target. However, this target aliases to Ra = 210-150 = 60 km, so the processor outputs 22122113221132232)/(====RRzRRRPcRRRPcRPczaaaa Substituting the numerical values we get z2 = 0.082z1. Thus, z2 is about –10 dBZ less that z1. Example 3 Reflectivity (dBZ) Velocity


View Full Document
Download Lecture Note
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Lecture Note and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Lecture Note 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?