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UK EE 211 - Transient Analysis - First Order Circuits

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Transient Analysis - First Order CircuitsTransient ResponseExamplesInstantaneous Voltage and Current Changes in Capacitors and Inductors:Switch Notation and Initial Conditions:Complete Solution by the Differential Equation ApproachExampleSlide 8Step-by-Step MethodKevin D. Donohue, University of Kentucky1Transient Analysis - First Order CircuitsSwitches, Transient Response, Steady-State Response, and Differential EquationsKevin D. Donohue, University of Kentucky2Transient Response DC analysis of a circuit only provides a description of voltages and currents in steady-state behavior.When the applied voltage or current changes at some time, say t0, a transient response is produced that dies out over a period of time leaving a new steady-state behavior.The circuit’s differential equation must be used to determine complete voltage and current responses.Kevin D. Donohue, University of Kentucky3ExamplesDescribe v0 for all t. Identify transient and steady-state responses. + v0 - + v0 - VDC t=0 t=0 R C Show:  0for volts0 0for voltsexp1)(0ttRCtVtvDCFor steady-state response, let t  , for transient response subtract out steady-state response.Kevin D. Donohue, University of Kentucky4Instantaneous Voltage and Current Changes in Capacitors and Inductors:What would be the required current, ic , in this circuit for the voltage on the capacitor to change instantaneously? What would be the required voltage, vL , in this circuit for the current in the inductor to change instantaneously? + vC - VDC ic t=0 C + vL - IDC iL t=0 L Conclusion: If the source cannot produce infinite instantaneous power, then neither the capacitor voltage, nor the inductor current can change instantaneously.Kevin D. Donohue, University of Kentucky5Switch Notation and Initial Conditions:In order to denote the time right before t=0 (limit from the left as t0), and the time right after t=0 (limit from the right as t0), the following notation will be used:Let t=0+ be the moment after the switch is closed and t=0- be the moment before the switch is closed.For circuits with practical sources, the voltage across a capacitor cannot change instantaneously,and the current in an inductor cannot change instantaneously)0()0(ccvv)0()0(LLii t=0Kevin D. Donohue, University of Kentucky6Complete Solution by the Differential Equation Approach5 major steps in finding the complete solution:Determine initial conditions on capacitor voltages and/or inductor currents.Find the differential equation for either capacitor voltage or inductor current (mesh/loop/nodal …. analysis).Determine the natural solution (complementary solution).Determine the forced solution (particular solution).Apply initial conditions to the complete solution to determine the unknown coefficients in the natural solution.Kevin D. Donohue, University of Kentucky7 ExampleFind the complete solution for iL for V10svvs t=0 0.25 H25 Show for t  0: ))100exp(1(4.0 tiL+vL-Kevin D. Donohue, University of Kentucky8ExampleFind the complete solution for vc when mA 1si t=0 t=0 R 100  1 mF is + vc - )10exp(1.0 tvcShow for t  0:Kevin D. Donohue, University of Kentucky9The solution of circuits containing energy storage elements can be divided into a steady-state and transient component. In addition, when only one energy storage element is present, the Thévenin resistance can be obtained with respect to the terminal of the energy storage element and used to compute the time constant for the transient component.Assume solution is of the form Assume steady-state before the switch is thrown and let either or , and find initial condition for quantity of interest Let = steady-state solution after switch is thrown, and , or tKKtx exp)(21)0()0(ccvv)0()0(LLii1K)0(x12)0( KxK thCR thRL Step-by-Step


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UK EE 211 - Transient Analysis - First Order Circuits

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