1Announcements I1. Exam #1 • Feb 18, Wednesday 8:20 pm – 10:10 pm. Please be there at least 10 minutes early.• Material from sections 1.1 – 5.3 of Serway/Vuille, 20 questions, multiple choiceUp to gravitational potential energy – no springs• If your last name begins with A through P, you should go to Carleton 100• If your last name begins with R through Z, you should go to Pugh 170• You are allowed one handwritten formula sheet (both sides), 8 ½”x 11”paper• Bring #2 pencil, eraser, a calculator and ID.• Sample exam from last semester posted on websiteAnnouncements II2. Special office hour tomorrow: Chan: 11am to noon and 3 – 4 pm3. HW set #5 is not due until Feb 25Note: Exam 1 may include material that is covered in the HW set (problems 5.28, 5,40, 5.78, 5.80, 5.85, and 5.92), so you are strongly encouraged to complete this set before Exam 1.4. Chan will give lectures until spring breakTest numberTest numberHITT RF Remote Login Procedure:1. PRESS AND HOLD THE DOWN ARROW KEY until the GREEN light on the remote turns RED.2. PRESS THE “0” KEY and you will see the RED light flash GREEN.3. PRESS THE “7” KEY and you will see the RED light flash GREEN.4. PRESS AND RELEASE THE DOWN ARROW KEY again and you will see the red light search for the receiver, if it BLINKS GREEN MULTIPLE TIMES you are logged in.The radio channel number for this room is “07” (zero, seven). It is STRONGLY recommended to login your remote for every class justto be sure it is on the correct radio channel and working before class.1. 7.2 m2. 1.3 m3. 25.2 m4. 0.3 m5. 0.1 m1. A tortoise can run with a speed of 10.0 cm/s, and a hare can run 20 times as fast. In a race, they both start at the same time, but the hare stops to rest for 4.0 minutes. The tortoise wins by a shell (30 cm). What is the length of the race? Clicker scores today will NOT count towards final grade.Unknowns: d = length of race t = time for tortoiseVtortoise= d/t = 0.1Vhare= (d-0.3)/(t-240) = 2 d - 0.3 = 2(t-240)d – 0.3 = 2(d/0.1 – 240)21. 40.0 m/s2. 23 m/s3. Need to know m4. 21.2 m/s2. In Bosnia, the ultimate test of a young man's courage used to be to jump (drop) off a 400 year old bridge (now destroyed) into the River Neretva, 23 m below the bridge. How fast was the jumper traveling upon impact with the river? Clicker scores today will NOT count towards final grade.Given: a, v0, ∆y, want vfvf2= vo2+ 2 a ∆y1. 58.9 m/s2. 2.28 m/s3. 5.60 m/s4. 4.20 m/s3. The driver of a truck slams on the brakes when he sees a tree blocking the road. The truck slows down uniformly with acceleration -5.6 m/s2for 4.20 s, making skid marks 58.9 m long that end at the tree. With what speed does the truck then strike the tree? Clicker scores today will NOT count towards final grade.Given: a, t, ∆x, want vfneed to find vofirst∆x = vot + ½ a t2thenuse vf=vo+ a t4. A track star in the broad jump goes into the jump at 12 m/s and launches himself at 20° above the horizontal.How long is he in the air before returning to Earth?1. 0.42 s2. 0.84 s3. 1.26 s4. 1.68 sClicker scores today will NOT count towards final grade.5. A plane is moving due north, directly towards its destination. Its speed in air is 200 mph. A constant breeze is blowing from west to east at 30 mph. At what speed is the plane moving north?1. 217 mph2. 202 mph3. 198 mph4. 193 mph5. 183 mphClicker scores today will NOT count towards final grade.6. Three forces, 5.0 N, 15.0 N, and 20.0 N, are acting on a 9.81-kg object. Which of the following forces could also be acting on the object if it is moving with constant velocity?1. 1 Newton2. 5 Newtons3. 19 Newtons4. 39 Newtons5. Any of the aboveClicker scores today will NOT count towards final grade.Directions are not given.The three forces could add up to a minimum of zero and a maximum of 5 + 15 +20 = 40 NConstant velocity == zero total forceThe magnitude of the fourth force can range from 0 to 40 N7. Two forces are applied to a car in an effort to move it, as shown in the figure. What is the resultant of these two forces? 1. 798 N, 8.8°2. 850 N, 0°3. 50 N, 180°4. 0 N30°Clicker scores today will NOT count towards final grade.3Atwood’s MachineFor objects connected by a massless string going over a massless pulley:1. Magnitude of tension is the same on both sides of the pulley.2. Magnitude of acceleration is same for both objects.T1T2T1= T2a1= a28. Two packing crates of masses m1 = 10.0 kg and m2 = 3.50 kg are connected by a light string that passes over a frictionless pulley as in the figure. The 3.50 kg crate lies on a smooth incline of angle 41.0°. Find the acceleration of the 3.50 kg crate. 1. 3.51 m/s22. 4.10 m/s23. 10.0 m/s24. 5.59 m/s2Clicker scores today will NOT count towards final grade.9. Acceleration has dimensions of…1. LT-12. LT23. LT-24. MLT-2Clicker scores today will NOT count towards final grade.10. A crate of mass 10.0 kg is pulled up a rough incline with an initial speed of 1.50 m/s. The pulling force is 100 N parallel to the incline, which makes an angle of 17.0° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 4.85m. (a) How much work is done by gravity? -139 J(b) How much mechanical energy is lost due to friction? 182 J(c) How much work is done by the 100 N force?485 J(d) What is the change in kinetic energy of the crate?164 J(e) What is the speed of the crate after being pulled 4.85 m?5.92 m/s Clicker scores today will NOT count towards final grade.Good