Unformatted text preview:

MA 153 Exam 1A Spring 200411. Evaluate.† 7 - 34 5( )- 62† A. 55B. 31C. - 41D. -17E. None of the above2. Simplify.† 4a5b-8c0( )-2a3b10c4( )† A. - 8a8b2c4B. -8a15c4b80C. a8b2c48D. a15c48b80E. -8a2b2c43. Simplify.† -3x-5y2x-1z-3Ê Ë Á ˆ ¯ ˜ 3† A. y5z69x7B. -27y6z9x12C. y6z927x18D. -9y5x4E. None of the aboveMA 153 Exam 1A Spring 200424. Simplify and rationalize the denominator, if appropriate.† 8a-3b63a-5† A. 2a7b36aB. 12b3a4C. b311a7aD. a7b311aE. 2b36a45. Perform the indicated operations and simplify.† 7x3- 4 x + 5( )- x 2x2+ 3( )† A. 5x3- 2x - 3B. 5x3- x + 5C. 5x3- 4 x + 8D. 5x3- 7x + 5E. None of the above6. Which of the following is a factor of † 27x6- y3?Hint: † x3- y3= x - y( )x2+ xy + y2( )† A. 9x4+ 3x2y + y2B. 3x2+ xy + y2C. 9x2- 3x2y + y2D. 3x4- 3x2y + y2E. 9x4+ 27xy + y27. Which of the following is a factor of † 12x2-11x - 5?† A. 2x -1B. 4 x + 5C. 3x +1D. 6x - 5E. 2x + 5MA 153 Exam 1A Spring 200438. Simplify the expression.† 5x-5x + hh† A. 1x + hB. h2x x + h( )C. 5h2x x + h( )D. 5x x + h( )E. 1x x + h( )9. Simplify. † 4 x2- 92x2-15x + 18÷2x + 3( )2x2-12x + 36† A. x -183 2x + 3( )B. 4 x + 25x + 2C. x + 6D. x - 65x + 2E. x - 62x + 310. Solve the following equation. Choose the answer that best describes the solution.† x - 4( )2+ 2x - 3 = x +1( )x - 3( )† A. x is between - 5 and - 3B. x is between - 3 and 0C. x is between 0 and 3D. x is between 3 and 5E. There is no solution for xMA 153 Exam 1A Spring 2004411. Solve † R = Q +hB for B.† A. B =hR - QB. B =Q + hRC. B = h R - Q( )D. B = Rh - QE. B =1h R - Q( )12. Solve the following equation for † x. Choose the answer that best describes the solution(s).† 4x - 5-3x + 5=7x + 5x2- 25† A. x is greater than 1B. x is between -1 and 1C. x is less than -1 D. There is no solution for x. E. All real numbers are solutions except x = -5 and 5. 13. An interior decorator charges $60 per hour while consulting on a job. Her assistant only charges† 23 of that amount per hour. On one particular job, the decorator worked five hours less than twicethe number of hours of her assistant. If the customer was billed for $850, find the number ofhours that the assistant worked. Round your answer to the nearest tenth.† A. 4.1 hoursB. 5.6 hoursC. 7.2 hoursD. 9.4 hoursE. None of the aboveMA 153 Exam 1A Spring 2004514. Two vehicles leave the same point traveling in opposite directions. The truck left first at 2:00p.m., traveling at a rate of 40 miles per hour. The car left the point at 3:30 p.m., traveling at a rateof 60 miles per hour. After how many hours past 2:00 p.m. will the two vehicles be 120 milesapart?† A. 2.1 hoursB. 0.3 hoursC. 1.8 hoursD. 0.6 hoursE. None of the above15. John inherits $45,000 and wishes to invest this amount in two accounts. The first account pays 6%simple interest, and will insure the entire $45,000. The second account pays a higher rate of 7.5%simple interest, but only insures deposits up to $30,000. Let † x represent the amount John investsat 6%. If the annual interest earned is to be $3,000, find the equation used to solve for † x.† A. 0.06x + 0.075x = 3000B. 0.06x + 0.075 45000 - x( )= 3000C. 0.06x + 0.075 30000( )= 3000D. 0.06 45000 - x( )+ 0.075x = 0.135 3000( )E. 0.06 45000( )+ 0.075 30000( )=


View Full Document

Purdue MA 15300 - Lecture notes

Download Lecture notes
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Lecture notes and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Lecture notes 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?