The uA741 Operational AmplifierOutlineBrief HistoryBrief History (cont)SchematicStagesInput Differential StageIntermediate Single-Ended High-Gain StageOutput Buffering StageCurrent Source / Short Circuit ProtectionDC AnalysisDC Analysis (cont)Slide 13Slide 14Slide 15Small Signal AnalysisSmall Signal Analysis (cont)Slide 18Slide 19PowerPoint PresentationSlide 21Slide 22Slide 23Slide 24Concluding RemarksThe uA741 Operational AmplifierOutline•Brief History•Stages•DC Bias Point Analysis•Small Signal Analysis•Concluding RemarksBrief History•1964 – Bob Widlar designs the first op-amp: the 702. –Using only 9 transistors, it attains a gain of over 1000–Highly expensive: $300 per op-amp•1965 – Bob Widlar designs the 709 op-amp which more closely resembles the current uA741–This op-amp achieves an open-loop gain of around 60,000.–The 709’s largest flaw was its lack of short circuit protection.Brief History (cont)•After Widlar left Fairchild, Dave Fullagar continued op-amp design and came up with the uA741 which is the most popular operational amplifier of all time.–This design’s basic architecture is almost identical to Widlar’s 309 op-amp with one major difference: the inclusion of a fixed internal compensation capacitor. •This capacitor allows the uA741 to be used without any additional, external circuitry, unlike its predecessors.–The other main difference is the addition of extra transistors for short circuit protection.–This op-amp has a gain of around 250,000SchematicStages•Input Differential Stage•Intermediate Signal-Ended High-Gain Stage•Output Buffering Stage•Current Source / Short Circuit ProtectionInput Differential StageThe input stage consists of the transistors Q1 through Q7 with biasing performed by Q8, Q9, and Q10. Transistors Q1 and Q2 are emitter followers which causes input resistance to be high and deliver the differential input signal to the common base amplifier formed by Q3 and Q4.Transistors Q5, Q6, and Q7, and resistors R1, R2, and R3 form the load circuit of the input stage. This portion of the circuit provides a high resistance load.Transistors Q3 and Q4 also serve as protection for Q1 and Q2. The emitter-base junction of Q1 and Q2 breaks down at around 7V but the pnp transistors have breakdown voltages around 50V. So, having them in series with Q1 and Q2 protects Q1 and Q2 from an accidental connection between the input terminals.Intermediate Single-Ended High-Gain StageThe second stage is composed of Q16, Q17,Q13B, and the resistors R8 and R9.Transistor Q16 acts as an emitter followergiving the second stage a high input resis-tance. Transistor Q17 is a common-emitter amplifierwith a 100-Ώ resistor in the emitter. The loadof this amplifier is composed of the output resistance of Q13B. This use of a transistoras a load resistance is called active load.The output of this amplifier (the collector of Q17) has a feedback loop through Cc. This capacitor causes the op-amp to have a poleat about 4Hz.Output Buffering StageThe Output Stage consists of the complimentary pair Q14 and Q20, and a class AB output stage composed of Q18 and Q19. Q15 and Q21 give short circuit protection(described later) and Q13A supplies current to the output stage.The purpose of the Output Stage isto provide the amplifier with a lowoutput resistance. Another requirementof the Output Stage is the ability to dissipate large load currents withoutdissipating large quantities of power.This is done through the class AB Out-put Stage.Current Source / Short Circuit Protection•Transistors Q11 and Q12 form one half of a current mirror that is used to supply current to the entire op-amp.•Transistor Q10 is used to supply a bias current to the Input Stage, Q13B supplies the Second Stage, and Q13A supplies the Output Stage.•Transistors Q15, Q21, Q24, Q22, and resistors R6, R7, and R11 make up the short circuit protection circuit. For a more detailed description see your text.(Microelectronic Circuits by Sedra / Smith 4th addition, pg 813)DC AnalysisReference Bias Current•This current is generated by Q11, Q12 and resistor R5. From these, we can write:•From this value of IREF, the current in the collector of Q10 can be calculated.•This value (IC10) is twice the value of I (which is used later in the DC analysis.IREFVccVbe Vbe Vee R5IREF0.733 mAGivenIC10R4 VTlnIREFIC10IC1018.421ADC Analysis (cont)Input StageUsing the value IC10 found before, the analysis unfolds as shown in the schematic.This analysis is done using the standard BJT, current mirror, and differential amplifier textbook equations.DC Analysis (cont)Second StageAssuming beta to be >> 0, the following DC biasing equations resultIC13B550 AIC13B0.75 IREFIC16IE16IB17IE17R8 VbeR916.2ADC Analysis (cont)Output StageUsing the fact that Q13A delivers ¼ of IREF, the following outputs result:If Vbe is assumed to be 0.7V, the current in R10 is 18uA which causes the following:Since the base current of Q18 is IC18 / beta = 165u / 200:IC23IE230.25 IREF 180AIC18IE18IC23IR10 162AIC19IE19IR10IB18 18.8ADC Analysis (cont)Table of ResultsBelow is a table that lists all of the transistors and their collector currents.DC Collector Currents of the 741 op-amp (uA)Q1 9.5 Q8 19 Q13B 550 Q19 15.8Q2 9.5 Q9 19 Q14 154 Q20 154Q3 9.5 Q10 19 Q15 0 Q21 0Q4 9.5 Q11 730 Q16 16.2 Q22 0Q5 9.5 Q23 730 Q17 550 Q23 180Q6 9.5 Q13A 180 Q18 165 Q24 0Q7 10.5Small Signal AnalysisTo better visualize the various small signal properties of the uA741 op-amp, a simple inverting circuit is constructed around the op-amp.This circuit is the circuit that will be used in the following analysis. It has a gain of 100 (Rf / R).Small Signal Analysis (cont)1. Frequency ResponseThe op-amp circuit is supplied by a 1mV AC signal and a Frequency analysis is performed.The inverting amplifier circuit outputs a gain of 100 until a frequency of 8kHz is reached. After this point, it attenuates at 20dB per decade until it reaches unity gain at 1MHz.Small Signal Analysis (cont)2. Transient analysisThe op-amp circuit is now supplied with a 1mV 1kHz sinusoidal source and a transient analysis is performed.The op-amp outputs a 100mV signal that is the exact inverse of the input signal. This verifies that the op-amp is indeed magnifying the signal appropriately as well as inverting the signal.Small Signal Analysis (cont)3. Monte Carlo