PowerPoint PresentationSlide 2Slide 3Slide 4Slide 5Slide 6Slide 7Slide 8Slide 9Slide 10Slide 11Slide 12Slide 13Slide 14Slide 15Slide 16Slide 17Slide 18Slide 19Slide 20Slide 21Slide 22Slide 23Slide 24Slide 25Slide 26Slide 27Slide 28Slide 29Slide 30Balanced Single Stub MatchingSlide 32Slide 33Slide 34Slide 35Slide 36ELEC 412 - Lecture 18 1ELEC 412 RF & Microwave EngineeringFall 2004Lecture 18ELEC 412 - Lecture 18 2ELEC 412 - Lecture 18 3ELEC 412 - Lecture 18 4ELEC 412 - Lecture 18 5ELEC 412 - Lecture 18 6ELEC 412 - Lecture 18 7ELEC 412 - Lecture 18 8ELEC 412 - Lecture 18 9ELEC 412 - Lecture 18 10ELEC 412 - Lecture 18 11ELEC 412 - Lecture 18 12ELEC 412 - Lecture 18 13ELEC 412 - Lecture 18 14ELEC 412 - Lecture 18 15ELEC 412 - Lecture 18 16ELEC 412 - Lecture 18 17ELEC 412 - Lecture 18 18ELEC 412 - Lecture 18 19ELEC 412 - Lecture 18 20ELEC 412 - Lecture 18 21ELEC 412 - Lecture 18 22ELEC 412 - Lecture 18 23ELEC 412 - Lecture 18 24ELEC 412 - Lecture 18 25ELEC 412 - Lecture 18 26ELEC 412 - Lecture 18 27ELEC 412 - Lecture 18 28ELEC 412 - Lecture 18 29ELEC 412 - Lecture 18 30ELEC 412 - Lecture 18 31Balanced Single Stub MatchingBecause of the parallel connection, the total admittance of the stubs will be double that of each leg, that is, Ybal = 2Ystub. A single unbalanced stub of length d can be converted into an equivalent balanced stub of length db by requiring that the two configurations provide the same admittance.ELEC 412 - Lecture 18 32Balanced Single Stub Matchingstubopenβdaπλdβdβdstubshortedβdaπλdβdβdbbbb2tantan2tantan22cotcot2cotcot2ELEC 412 - Lecture 18 33Unbalanced Single Stub MatchingELEC 412 - Lecture 18 34Balanced Single Stub MatchingELEC 412 - Lecture 18 35ELEC 412 - Lecture 18
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