PHYS 211 Lecture 11 Outline of Last Lecture I. Newton’s 2nd LawOutline of Current LectureI. Newton’s 2nd Law Practice Problems Current LectureI. Newton’s 2nd Law Practice ProblemsA force acts on a 1.5 kg mass, giving it an acceleration of 3m/s2. If the same force acts on a 2.25 kg mass, what accleration will be produced?F1=m1a1 F2=m2a2 = (3kg)(1.5m/s2) a = F2/m2 = 4.5N = (4.5N)/(2.25kg) = 2.0m/s2Two masses are attached to a string and on a pulley. Write the equations for the net force in terms of the components. y = ∑F = Fnet FN-m1g(cosθ) = m1ay N = m1g(cosθ)x = ∑F = Fnet T = m1g(sinθ) = m1ax These notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.Break down the force into x and y components x = ∑F = Fnet T2sinθ – T = ma T1 = T2sinθy = ∑F = Fnet T2cosθ – T1 = ma T2 =
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