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TAMU CHEM 101 - Exam2x-103
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Chemistry 101H Hour Exam 2 Fall,2008 Dr. Watson Constants and Conversion Factors: e2 = 14.4 eV-A. = 2.307xlO-28 J-m h = 6.626xlO-34 J-s = 4. 136xlO-15 eV-s hc = 12398.42 eV-A. = 1.986x10-25 J-m mass of electron = 9.109xlO-31 kg mass of proton = 1.673x10-27 kg tjJ(x) (2/a)I/2 sin (mexia) I 2 HeH 4.00261.0080 7 103 4 5 6 8 9 N NeLi Be B C F0 10.811 12.011 14.007 15.999 18.998 20.1836.939 9.0122 II 13 1812 14 15 16 17 Na Mg AI Si P ArS Cl 22.990 24.312 26.982 28.086 30.974 32.064 35.453 39.948 19 20 21 22 24 26 27 3123 25 28 29 30 32 34 3633 35 K Ca Sc Ti V Cr Mn Fe Ni Cu Ga SeCo Zn Ge As Br Kr 39.102 40.08 44.956 47.90 50.942 51.996 54.938 55.847 58.933 58.71 63.54 65.37 69.72 74.922 7896 79.909 83.8072.59 37 42 4438 39 40 41 43 45 46 47 49 51 52 5448 50 53 Rb Y Zr Nb MoSr Tc Ru Rh Ag In XePd Cd Sn Sb Te I 85.47 87.62 91.22 95.94 (98) 107.8788.905 92.906 101.07 102.91 106.4 112.40 114.82 118.69 121.75 127.60 126.90 l3l.30 55 7156 72 73 74 75 7776 78 79 81 82 8480 83 85 86 Cs Ba Hf W Re IrTa Os Pt Au Hg TI Pb Bi Po RnAt'" Lu 132.91 137.34 174.97 178.49 190.2 192.2 (210)180.95 18385 186.2 195.09 196.97 200.59 204.37 207.19 208.98 (210) (222) 87 88 103 104 106 107105 108 109 Fr Ra Rf Sgt Lr Db Bh Hs Mt (223) (226) (261) (262) (263)(262) (262) (265) (266) * Lanthanide Series t Actinide Series 57 58 59 60 61 62 63 64 65 66 67 68 69 70 La Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb 138.91 140.12 140.91 144.24 (147) 150.35 151.96 157.25 158.92 162.50 164.93 167.26 16893 173.04 89 90 91 92 93 94 95 96 97 98 99 100 101 102 Ac Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No (227) 232.04 (231) 23803 (237) (242) (243) (247) (247) (251) (254) (257) (258) (259) Name _-=-kE=-£_y~ _ Eo = 13.606 eV <lo = 0.529 A. 1 eV = 1.602x10-19 J mc2 for an electron =511 keV mc2 for a proton = 938 MeV---1 1. The following questions refer to an electron in a box (i.e., in an infinite potential well) having a width of 1.5 A. a). Calculate the kinetic energy of the electron when it is in the n = 1 energy level. s b).Absorption of a photon having a wavelength of 49.5 Araises the electron to a higher energy level. What is the n value of this energy level? s c). What is the maximum value of tjJ2 when the electron is in the n = 5 energy level. <;i:: Z :: 2 ,a;",.. 2...2'.!lU. ~~u/~-=i 5 a.. a. _ 2 - ~ y.. 24 )-1MIt' -a: -/.S -..3 d).What is the probability of finding the electron between 0.3 Aand 0.45 Awhen it is in the n = 5 energy level? ~~ ~ S~.J,c..ruA. ~ 6X= ";[=.0. 3 ,l D.t> 5 --L 10 e). What are the boundary conditions on the wavefunctions for a particle in a box? ~ (.0) == 05-~(Oo..) ::: 02 2. The following questions refer to a hydrogen atom. a). Calculate the total energy when n = 6. s-~~ = -L3.(P (:i;) 2. -O. 378~V b).How many sets of quantum numbers (n, Q, me, ms) are there for n =6? 5-2n"2. = 2(360) =-7Z c). One of the radial wavefunctions for a hydrogen atom is shown below; 0.20 0.15 -"-~ 0.10 0.05 0.00 -0.05 -0.10 0 5 101520 25 30 r (Angstroms) • This wavefunction has &:J nodes • The value of Q for this wavefunction is 0 • The value of n for this wavefunction is .:) o • The most probable radius of an electron in this orbital is approximately 20.43 Y(8,¢) = N sin28 cos 2¢. For what value(s) of 8 does this wavefunction have its maxiumum value? • -• For what value(s) of ¢ does this wavefunction have its maxiumum value? 2~ = 0 ) 7TJ 2~ ~ IT 41 =. 0 .IT) IT) .isr eXt ~ y ~)J I ~ \ Z. • Circle the orbital picture below that depicts this angular wavefunction. ,I, ,I, d\"o (a) (b) (c) d. , \. (d) (e) 3. a). Write an equation for the potential energy of a lithium (Li) atom. -€.-Jr:-5'-V== -3e4( ~I + t~ -;=;) + e"' ( ;,~ + ~~ +-L)rt3 -€.-4 b). What are the possible values of the Z-components of the orbital angular momentum '5 vector (Lz) when Q = 3 L 1!: = >?'&1;, L2-=: 3~) "2"h J ~ ) 0) -1\:) - z11.) - 3 ~ c). Write the ground state electron configuration of 83Bi. How many unpaired electrons S does a ground state Bi atom have? -4. Select answers to the following questions from the elements listed below 63Eu 74W 16S 51Sb uNa 18Ar 20Ca 2He l7CI 56Ba 35Br • The element with the highest electronegativity is c.e. • The element with the highest ionization potential is #e • The element with the largest electron affinity is d-• The element that has a half-filled f subshell is EeL • The element that has a maximum and minimum oxidation number of 3-and 5+, respectively, is Sb • The element whose oxide reacts with water to produce OH-is _M-:...-__ • The element with the largest radius is .Ba... 5. a). The following reaction takes place in basic solution: \2e \ +"7 -8 ~ -8 i-<t -4 ~ -'-11,.0 -{-L.Mn04-+3-e30 4 --+ ZMn02 +J'3Fe20 3 + 20/1sI 1-+3e c;...~ '.• Balance this reaction. 1-1-: • What element is oxidized? 0', - 35 5 b). Draw three Lewis dot structures that satisfy the octet rule for the molecule OCS. (You may not switch the atoms around). -soc..s ~+4 ~&=/~~ o S: 3 (8) -/~ :::.. 8 o ...,':1"'. O=--C-=S .... I 0 ... -1 =O=.C-S~.. -I.. 0 ..... :O-c.=.S-:... c). Predict which structure has the lowest energy and rewrite it below showing the formal charge of each atom. • ~ C' ~. ~~~ 0= c.=


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