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UB PHY 101 - Free Falling Objects

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PHY 101 1nd Edition Lecture 6 Outline of Last Lecture I. One Dimension Motion With Constant AccelerationII. Kinematic EquationsIII. Free Falling Objects Chapter 2 Continued; Chapter 3: Motion in Two DimensionsIV. Free Falling ObjectsV. Problem Solving StrategiesVI. 3.1 Vectors and PropertiesVII.Adding VectorsCurrent Lecture- Free Falling Objectso Can be used with kinematicso Ex. If a ball is thrown vertically up with a Vo = 9.8 m/s A. how long does it take to reach the highest point?- V = Vo + at- T = (V – Vo)/a- T = (0 – 9.8)/-9.8 = 1s B. what is the maximum height?- V2 = Vo2 + 2aΔy- Δy = V2 - Vo2/ 2a = (0 - 9.8) /2(-9.8) = 4.9 mo Ex. A ball is released from rest from a 19.6 m building. A. how long does it take to reach the ground? Known: yo = 19.6m, y = om, Vo = 0 m/s, a = -9.8 m/s2- Y = yo + vot + (1/2)at2- 0 = 19.6 + 0 + (1/2)(-9.8)t2- T2 = (2(-19.6)/ -9.8)- T = 41/2 = 2s B. what is the velocity when the ball reaches the ground?- V = Vo +atThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.- V = 0 + (-9.8)(2)- V = -19.6 m/s- Problem Solving Strategieso Read very carefullyo Draw a diagram**o Use kinematicso Solve for unknownChapter 3: Vectors and Motion in Two Dimensions- Vectors have both direction and magnitude- Vectors are noted with arrows above the letters- Propertieso Equality: same magnitude, same unit, same direction- Adding Vectorso Must have the same units/dimensionso Rule: triangle method (tip to tail)o C = A + B (sides A and B are tip to tail)o The negative of a vector runs in the opposite direction A-Ao Vector Subtraction- A – B = A + (-B)o Multiplying/ dividing by a scalar quantity ( a number)- Magnitude of the vector is multiplied/divided by that


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UB PHY 101 - Free Falling Objects

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