DOC PREVIEW
UIUC ECON 203 - Hypothesis Testing

This preview shows page 1 out of 2 pages.

Save
View full document
View full document
Premium Document
Do you want full access? Go Premium and unlock all 2 pages.
Access to all documents
Download any document
Ad free experience
Premium Document
Do you want full access? Go Premium and unlock all 2 pages.
Access to all documents
Download any document
Ad free experience

Unformatted text preview:

ECON 203 1st Edition Discussion - Lecture 2Outline of Last LectureI. Descriptive Statistics Review1. Population2. SampleII. Descriptive Statistics Measurements1. Central Tendency Measurei. Meanii. Medianiii. Mode2. Example Slide 9i. #1ii. #23. Dispersioni. Rangeii. Variance iii. Standard Deviation4. Linear Associationi. Covarianceii. Correlation CoefficientIII. Skewed Graphs1. Right2. LefIV. Empirical RuleOutline of Current Discussion LectureI. Review of key class features1. Office Hours 2. HomeworkII. Aplia Homework 21. Hypothesis Testing, Example 12i. Relevant Point Estimateii. Value of Test Statisticiii. P-valueiv. Type I error conclusionCurrent Discussion LectureThese notes represent a detailed interpretation of the professor’s lecture. GradeBuddy is best used as a supplement to your own notes, not as a substitute.I. Review of key class features1. Office hours - Posted this week and will be Monday – Thursday- TA’s will be rotating office hours2. Homework- Afer this week there will be only one homework assignment due each week of the semesterII. Aplia Homework 21. Hypothesis Testing, Example 12i. Relevant point estimate- This variable is found by taking the number of customers who purchased the glass and divide it by the total- 151/950 = .1589 … = .159ii. Value of Test Statistic- Use the “z” variable equation- P = .15 because that is the population standard- Z = (p-hat – p)/ sqrt((p(1-p))/n)- Z = (.159 - .15)/sqrt((.15*.85)/950) = .7723iii. P-value- All tests about proportion use a z statistic, so this test statistic follows a standard normal distribution- In excel put =NORMSDIST(z) . This will return the area to the lef of “z”- NORMSDIST(.7723) = .7800 …. 1-.7800 = .2200iv. Type I error conclusion- Allowing for a 5% chance of error- Which means that 95% of the experiment must be correct in order for the company to pursue this line of cartoon mugs- Do not reject the null hypothesis, and conclude that there is insufficient evidence that the special offer should be introduced- The p-value is not less than alpha=.05, therefore conclude that there is insufficient evidence that the special offer should be


View Full Document
Download Hypothesis Testing
Our administrator received your request to download this document. We will send you the file to your email shortly.
Loading Unlocking...
Login

Join to view Hypothesis Testing and access 3M+ class-specific study document.

or
We will never post anything without your permission.
Don't have an account?
Sign Up

Join to view Hypothesis Testing 2 2 and access 3M+ class-specific study document.

or

By creating an account you agree to our Privacy Policy and Terms Of Use

Already a member?