Lab 2: Lenses and Geometric Optics2.12.14 Physics 132 In-lab DataPart 2.1Snell’s LawFirst laser:1 = 30, 2 = 30, 3 = 231.00029*sin30 = n2 * sin23n2 = 1.28actual; 1.33second laser:1 = 40, 2 = 40, 3 = 351.00029*sin40 = n2 * sin35n2 = 1.12Part 2.3Focal LengthF= 10.5 cmReal imagesFirst image recording:S = 13 cmS1 = 37 cmh = 3.9 cmh1 = 9.2 cm1/s + 1/s1 = 1/f1/13 + 1/37 = 1/ff= 9.62-(s1/s) = h1/h-37/13 = -9.2/3.9-2.84 = -2.35second image:S = 15 cmS1 = 31 cmh = 3.9 cmh1 = 8.3 cm1/s + 1/s1 = 1/f1/15 + 1/31 = 1/ff=10.1-(s1/s) = h1/h-31/15 = -8.3/3.9-2.0667 = -2.128third image:S = 19 cmS1 = 21.5 cmh = 3.9 cmh1 = 4.5 cm1/s + 1/s1 = 1/f1/19 +1/21.5 = 1/ff=10.1-(s1/s) = h1/h-21.5/19 = - 4.5/3.9-1.13 = -1.15Image Location by ParallaxS1 = 25 cmS = 16.51/16.5 + 1/25 = 1 /ff=9.93Virtual ImageThe image is larger and it is inverted (not upright)2.4 Diverging (concave) lensThe image is upright and it is a lot smaller.Lens combinationsS= 28S1 = 401/28 + 1/40 = 1/ff combined = 16.471/16.47 = 1/9.94 + 1/fdfd = -25.07The result is negative and greater. This makes sense because it a longer focal length takes longer to
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