Principles of Chemistry II © Vanden BoutFor the following reaction ΔRG° = -542 kJ mol-1 at 298KIf I start out with a contain that has a pressure of 1 atm of H2(g) and 1 atm of F2(g),at equilibrium what will the partial pressure of HF(g) be?H2(g) + F2(g) 2HF(g)! A.! ! approximately 1 atm ! B.! ! approximatley 0 atm! C.! ! approximately 2 atm! D.! ! approximately 4 atm! E.! ! there is no way to knowPrinciples of Chemistry II © Vanden BoutFor the following reaction ΔRG° = +740 kJ mol-1 at 298KIf I start out with a contain that has a pressure of 1 mole of Fe2O3,at equilibrium how much solid Fe will I have?Fe2O3(s) 2Fe(s) + (3/2)O2(g)! A.! ! approximately 0 moles ! B.! ! approximatley 1 moles! C.! ! approximately 2 moles! D.! ! approximately 3/2 moles! E.! ! there is no way to knowPrinciples of Chemistry II © Vanden BoutFor the following reaction what is the change value for H2O?2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(g) R C2H6 O2 CO2 H2OI 1.0 1.4 1.8 0 C -2x ? ? ?! A.! ! -2x ! B.! ! +2x! C.! ! +3x! D.! ! +6xPrinciples of Chemistry II © Vanden BoutFor the following reaction what is the equlibrium value for CO2?2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(g) R C2H6 O2 CO2 H2OI 1.0 1.4 1.8 0 C -2x ? ? ?! A.! ! 1.8 - 2x ! B.! ! 1.8 + 2x! C.! ! 1.8 + 4x! D.! ! 1.0 + 6xPrinciples of Chemistry II © Vanden BoutAcids and BasesBrønsted-Lowry DefinitionAcid is a proton (H+) donorBase is a proton (H+) acceptorPrinciples of Chemistry II © Vanden BoutFor exampleHydrochloric Acid
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