Math 111Professor: FaulknerSi Instructor: Colleen MaguffinExam 1 ReviewOn sections A.1-A.4, B.2, B.3, C.1-C.3, 1.3-1.7.*Be Sure to Look over Questions that are “Potential Test Questions”A.1Evaluate the arithmetic expression1. -2 + [4*7-5(9-8/2)]2. 3(4*6-2*10)+7(15-8*2)3. 1-2[3-4(5-6*7)]Expand using the distributive property4. 4mn(2p+3pq-2q)5. -3c(6ab-5bd)6. (3q-2qr-5r)(-2ps)A.2Find the indicated set if A=[1,2,3,4,5,6,7}, B={2,4,6,8}, C={7,8,9,10}a. A U Bb. B U Cc. A U Cd. A U B U Ce. A ∩ Bf. B ∩ Cg. A ∩ Ch. A ∩ B ∩ CDescribe the Intervals and Graph.1. (-3,0)2. [2,8)3. (-∞,-2)4. (-∞,1)5. [-3, ∞)6. [-6, -1/2]Express in interval notation and Graph.1. 1≦x≦22. -2<x≦13. x>-14. x≥-5A.3Use the rules of exponents to write each expression in as simple a form as possible.1. 23*22 2. (23)03. (107)/(104)4. (75*7-3)/(72)5. (2/3)-3Simplify each expression, and eliminate any negative exponents.1. x8x22. (2a3a2)43. (y10y0)/y74. (3x4/4x2)A.4Simplify and eliminate any negative exponents(s). Assume that all letters denote positivenumbers.1. (w4/3/w1/3)2. (27/k3)-1/33. (3a2/3)2Simplify the expression and express the answer using rational exponents. Assume all letters denote positive numbers.1. √(x3) √(x5)2. √(xy)/ 4√(16xy)B.2Factor the trinomial.- 8x2+10x+3Factor each expression- 2x2+5x-3Use the Difference of Squares Formula to factor the expression- 4x2-25Factor the perfect square1. y2+10y+25*We will look at more examplesFactor the expression completely1. 2x3+8x2+8x2. x4+2x3-3x2Factor by grouping1. x3+4x2+x+42. 2r3+r2-6r-33. y3-y2+y-1B.3Simplify1. (5y2)/(10y+y2)2. 4(x2-1)/12(x-2)(x-1)3. (y2-3y-18)/(y2+4y+3)Perform the operation and simplify1. (x2+2x-3)/(x2-2x-3) * (3-x)/(3+x)2. 5/(2x-3) - 3/(2x-3)2C.1Solve the equation.1. (2x-7)/(2x+4) =(2/3)2. 6/(x-3)=5/(x+4)C.2Solve by factoring.1. 3x2-5x-2=0Solve by completing the square.2. X2-6x-11=03. 3x2-6x-1=04. 2x2+8x+1=05. 4x2-20x-2=0Solve by using the quadratic formula.1. X2+3x+1=02. 2x2-8x+4=0C.3Solve the linear equality.1. 3x+11< 52. -1<2x-5<7Solve the nonlinear equality.1. (x-4)(x+2)2<02. (x-5)(x-2)(x+1)>01.3A mountain climber knows that the higher the elevation, the colder is the temperature. Table 2 gives data on the temperature at different elevations above ground level on a certain day, gather by using weather balloons.a) Show that a linear model is appropriate for these datab) Find a linear model for the relationship between temperature and elevationc) Draw a graph of the equation you found in part (b)Table 2.Elevation (km) Temperature (C)0 201 102 03 -104 -205 -301.4Two-variable data are given in the table.a) Explain why the variable y is a function of the variable x.b) Find the net change in the variable y as x changes from 0 to 5.c) Find the net change in the variable y as x changes from 3-5.1. x y0 21 02 33 44 25 12. x y0 61 62 63 64 55 56 57 5*Be able to determine whether a graph is a function or not based on the vertical line test.1.5Express in function notation.- “Square, add 7, then divide by 4.”Give a verbal description of the function.- K(w)=(w+1)2-9Evaluate at the indicated values.- S(x)= 1/√(x+1)a) S(0)b) S(3)c) S(4)d) S(a)Find the Domain1. 1/(3x-6)2. √(x+9)3. √(2+x)/(3-x)*Be able to evaluate piecewise functions at certain values.1.6 & 1.7Currently Learning we will go over in the review what we accomplish in