M5 Lab Report VI 1 M glider 299 5 g M weight hanger 5 1 g Section VI 1 M2 M M g M hanger g 0 5 10 15 20 25 2 s m c n o i t a r e l l e c A 100 90 80 70 60 50 40 30 20 10 0 a4 a3 a5 a2 a1 13 13 3 13 4 13 4 13 3 5 27 27 4 28 1 27 8 27 1 41 42 5 43 2 43 4 44 5 4 56 54 9 55 1 8 56 2 67 2 69 7 67 9 68 8 68 6 84 90 8 85 9 87 3 83 1 55 5 1 10 1 15 1 20 1 25 1 30 1 M g VS a cm s 2 f x 2 86 x 1 28 R 1 0 5 10 25 30 35 15 20 Mass g Slope s 2 8615 0 0609 Y Intercept b 1 2821 N M 1 g 1 1914 T M 1 a The force in the x direction is only the tension of F T and F m a F M 2 a M 2 a M 2 g T M 2 g M 2a T subsituting for T M 2 g M2 a M 1a M 2 g M 1a M2 a M 2 g a M 1 M2 M 2 g M1 M 2 g s M 2 a Thereforethe slope is M 2 g M1 M 2 M 1 M 2 so so s g Calculations VI 1 M 1 M2 329 6 g g 2 8615 329 6 g 943 1504 cm s2 g 114 69448 2 2 s M 1 M2 M 1 M 2 g g s g 943 1504 0 0609 2 8615 M 1 M2 g 20 0734 0since the mass is constant 2 2 0 329 6 g g 943 1504 20 0734 cm s2 The uncertainty for g does not fall within the accepted value but it is very close
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