UB PHY 151LAB - Physics M6 Lab Report
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VI 1 1 2 3 4 5 6 7 8 9 10 m1 156 2 grams m2 155 9 grams Speed Gate 1 cm s Speed Gate 2 cm s Trial Initial Initial Final 15 3 35 7 27 3 36 6 23 33 8 31 7 36 2 40 6 32 3 Final 20 29 2 36 6 15 5 22 7 26 3 25 5 13 5 22 7 42 5 30 7 43 4 50 7 29 4 32 3 38 6 37 8 25 6 30 3 59 5 0 24 3 18 3 26 5 15 1 24 6 20 9 26 7 32 22 Trial Pi g cm s Pf g cm s P g cm s P Pi 1 2 3 4 5 6 7 8 9 10 2396 27 1189 72 3639 87 1133 46 1442 97 738 18 941 48 1663 4 1617 95 4230 79 3124 772 67 2863 95 1710 25 1191 65 272 92 724 79 2053 83 1443 06 3208 7 727 73 417 05 775 92 576 79 251 32 465 26 216 69 390 43 174 89 1022 09 0 30369282 0 3505447 0 2131724 0 50887548 0 1741686 0 6302799 0 2301589 0 23471805 0 1080936 0 2415837 Calculations for Trial 1 Initial Momentum We use the equation pi m1 1 i m2 2i Final Momentum pf m1 1 f m2 2 f Thus we have pi 156 2 15 3 155 9 30 7 2396 27 g cm s We use the same equation as in the previous step to find this value but this time use the final velocity values for each gate instead of the initial velocity values So we have pf 156 2 20 155 9 0 3124 g cm s Change in Momentum To find the value for the change in momentum we must use the equation P Pf Pi Thus we have the following calculation for trial 1 on the next page P Pf Pi P 3124 2396 27 727 73 g cm s P Pi Ratio of We use the equation P Thus we have the following calculation Po P Pi 727 73 2396 27 0 30369 All the other trials were calculated using the same methods as shown above for initial momentum final momentum change in momentum and the ratio of P Pi Trial 1 2 3 4 5 6 7 8 9 10 KEi J 91749 5245 246361 171 258576 845 171996 498 122639 356 205366 946 189859 987 153430 676 200302 032 357443 437 KEf J 31240 KE J 60509 5245 112619 88 133741 2915 130724 312 73503 9125 58017 5285 101193 211 84833 8645 69803 5005 120064 949 178795 925 127852 533 98492 5855 64621 827 104173 735 105026 1225 83627 1755 80237 0825 178647 5115 KE KEi 0 6595078 0 5428668 0 494447 0 572643 0 5269257 0 5072566 0 5531767 0 5450486 0 4005805 0 4997924 Calculations for Trial 1 Initial Kinetic Energy We use the equation KEi 1 2 m1 1i2 1 2 m2 2i2 Thus we have the following KEi 1 m2 2i2 1 2 2 m1 1i2 1 2 156 2 15 3 2 1 2 155 9 30 7 2 91 749 52 J Final Kinetic Energy Follows the same process as initial energy but we instead use final values instead of initial values Thus we have KEf 1 m1 1 f 2 1 2 2 m2 2f 2 1 2 156 2 20 2 1 2 155 9 0 2 31 240 J Change in Kinetic Energy We use the formula KE KEf KEi Thus we have KE KEf KEi 31 240 91 749 52 60 509 52 J Ratio of KE KEi We use the formula KE KEi Thus we have KE KEi 60 509 52 91 749 52 0 6595078 All the other trials were calculated using the same methods as shown above for initial kinetic energy final kinetic energy change in kinetic energy and the ratio of KE KEi VI 2 m2 155 9g m3 287 8g Trial 1 2 3 4 5 6 7 8 9 10 1 2 3 4 Speed Gate 1 cm s Speed Gate 2 cm s Initial 41 1 35 7 32 47 8 26 3 32 3 39 5 31 1 36 2 30 9 7884 31 1481 7 1102 8 4480 79 Final 5 1 20 5 19 9 20 1 17 7 22 1 16 5 11 7 5 4 12 7 4783 81 1271 5 1070 02 4005 74 Initial 25 3 56 4 52 59 5 48 5 56 4 50 7 36 9 29 4 39 3100 5 210 2 32 78 475 05 Final 40 1 46 43 6 62 8 33 8 44 4 45 8 38 3 44 35 4 0 3932494 0 1418641 0 0297243 0 1060193 Trial Pi g cm s Pf g cm s P g cm s P Pi 5 6 7 8 9 10 7 99 503 18 3463 97 3197 87 5834 9 2812 92 175 36 561 58 2391 52 2603 71 5305 48 1863 8 167 37 58 4 1072 45 594 16 529 42 949 12 20 9474343 0 11606185 0 3096014 0 1857987 0 0907333 0 3374145 Calculations for Trial 1 Initial Momentum We use the equation pi m3 3i m2 2i Thus we have pi 287 8 41 1 155 9 25 3 7884 31 g cm s Final Momentum We use the same equation as in the previous step to find this value but this time use the final velocity values for each gate instead of the initial velocity values So we have pf m3 3 f m2 2 f 287 8 5 1 155 9 40 1 4 783 81 g cm s Change in Momentum To find the value for the change in momentum we must use the equation P Pf Pi P Pf Pi 4783 81 7884 31 3100 5 g cm s Ratio of Thus we have the following calculation P Pi We use the equation P Thus we have the following calculation Po P Pi 3100 5 7884 31 0 3932494 All the other trials were calculated using the same methods as shown above for initial momentum final momentum change in momentum and the ratio of P Pi Trial KEi J KEf J KE J KE KEi 1 2 3 4 5 6 7 8 9 292972 3345 129087 2185 163885 116 0 5593877 431354 943 225416 175 205938 768 0 477423 358130 4 205165 671 152964 729 0 4271202 604750 9635 365559 367 239191 5965 0 3955208 282892 0785 134135 629 148756 4495 0 5258417 398085 263 223949 711 174135 552 0 4374328 424889 6705 202687 813 222201 8575 0 5229637 245319 0185 134042 5465 111276 472 0 453599 41153 952 155107 324 113953 372 2 76895332 10 255959 109 120893 453 135065 656 0 5276845 Calculations for Trial 1 Initial Kinetic Energy We use the equation KEi 1 2 m3 3i2 1 2 m2 2i2 Thus we have the following m2 2i2 1 KEi 1 2 2 m3 3i2 …

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# UB PHY 151LAB - Physics M6 Lab Report

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