MINES CHEN 201 - Lecture 30 Canvas

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Mastering Maintenance Fri 4 16 11 pm Sat 4 17 7 am Class 30 Monday April 5 Hope you had a wonderful break Today s Coverage 17 7 17 8 Bases Salts Helpful items for today Equations sheet located on Canvas Pencil pen and paper or tablet Reef open and ready to go Calculator Today begins Unit 3 LME 2 material through 3 26 F 4 9 lecture guided review session Dr Beren s 4 pm office hours cancelled today 8 pm will still be held Mastering Problem Set 6 Chp 17A Due Wed 4 7 at 10 pm MT Additional Optional Resources Video Helps by Professors J2 for Chps 15 16 and 17A Practice Problem Sets for Chps 15 16 and 17A Mastering for Chps 15 16 17A Lecture Notes Pace your studying LME 2 April 12 M 7 30 9 pm MT Chapters 15 16 17A pace your preparation ACS LME 2 Help Session Wed April 7th from 5 7pm Fri April 9th 1 3 pm Weekend sessions with Dr Beren Sat and Sun at 8 pm Coverage Chp 15 16 17 1 17 6 Final LME May 7 Friday 8 10 am Updated grade calculator posted use only the updated No quadratic or polynomial calculations on LME perfect squares or x is small In class review on Fri 4 9 LME 2 Resources and Logistics page is available located next Unit 2 link on the homepage HA aq H2O l H3O aq A aq Acid 3 O H lo g H p Strong Acid calc pH Weak Acid calc pH EQ conc Ka Mixture of Acids strong strong strong weak weak weak Percent Dissociation pH log H3O HA initial H3O eq pH dissociation HA initial H3O eq pH dissociation Strong Acid HCl aq H2O l H3O aq Cl aq Weak Acid HF aq H2O l n a I C n a E 1 00 x n a 1 00 x H3O 0 x x aq F 0 x x aq H3O A Ka HA x 2 HA i x Ka H3O x pH log H3O Partial dissociation H3O HA initial pH log H3O 100 dissociation Determine the pH of an aqueous solution of 0 075 M HNO3 a 0 075 b 1 12 c 6 35 d Not enough information provided Strategy Weak or Strong Dissociation H3O HA initial pH log H3O Answer b Determine the pH of an aqueous solution of 0 075 M HNO2 Ka 4 6 x 10 4 a 0 75 b 1 12 c 2 23 d Not enough information provided Strategy Weak or Strong Ka H3O A HA x Ka x 2 HA x x H3O pH log H3O Answer c Dissociation 0 0059 M 0 075 M 100 7 9 HA aq H2O l H3O aq A aq Strong Acid calc pH Weak Acid calc pH EQ conc Ka Mixture of Acids Acid 3 O H lo g H p strong strong strong weak weak weak Percent Ionization What next BASES A aq H2O l OH aq HA aq Kb base constant Kb OH HA A Base into Water H 3 O H lo g O H lo g H p O p Strong base Kb infinite More OH 1 Weak base Smaller Kb Less OH 1 100 reaction Partial reaction Strong Base Na NaOH aq H2O l aq OH aq OH B initial pOH log OH pH 14 pOH aq Weak Base OH 1 00 x NH3 aq H2O l aq NH4 0 n a I 0 C n a x x x E x n a OH NH4 1 00 x Kb Kb NH3 x 2 B init x OH x pOH log OH pH 14 pOH A aq H2O l OH aq HA aq Base Strength and the Base Constant Kb W O b h y n o K o n e or t w H u nit O hic h is th e B stro n g e st W bis ote K ater N b as e in w W A aq H2O l OH aq HA aq Strong or Weak Base H 3 O H lo g H H lo g O p p O Strong Base OH OH initial pOH log OH pH 14 pOH Strong Base calc pH Weak Base calc pH EQ conc Kb Mixture of Bases strong strong strong weak weak weak Weak Base x 2 B init x Kb OH x pOH log OH pH 14 pOH pH log H3O pH 7 is acidic pH 7 is basic pH 7 is neutral Kw H3O OH 1 0 x 10 14 log H3O OH log 1 0 x 10 14 pH pOH pKw pH pOH 14 00 At 25oC pOH log OH pOH 7 is basic pOH 7 is acidic pOH 7 is neutral log gives p fu nctio n m ore co n d e nse d ra nge pKa log of Ka pKb log of Kb pKw log of Kw The stronger the acid Ka pKa The stronger the base Kb pKb What is the pH of a 0 116 M solution of Ba OH 2 OH 2 Ba OH 2 2 0 116 M 0 232 M pOH log OH log 0 232 0 6345 pH 14 00 pOH 13 37 Strategy Weak or Strong Strong Base OH OH initial pOH log OH pH 14 pOH What is the pH of an aqueous solution containing 0 050 M KOH and 0 015 M Sr OH 2 A 13 00 B 12 96 C 12 69 D 12 90 E 13 29 Strategy Weak or Strong Check Point Be ready to click with Reef on Wed Calculate the pH of a 15 0 M solution of NH3 Ka 5 56 x 10 10 A 13 0 B 12 2 C 1 8 D 0 0164 E 10 4 Strategy Weak or Strong Check Point Be ready to click with Reef on Wed


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