Problem set #3SolutionCHE 425 __________________ LAST NAME, FIRSTProblem set #31-8 Copy the program UnitOp3.exe from the CHE 425 class distribution folder to your flashor H drive. You can also download the program from the website: https://www.csupomona.edu/~tknguyen/che425/homework.htm. Run the program and choose problem 1-8 in any order. Solve the problems with the dataprovided by the program, copy the problem statement to Word. The program will check youranswer and provide an answer code when you click on “Check”. Copy the answer code andpaste them after the problem statement. You need to present all your work with a diagram indetails to get full credit. Your work should look like this:CHE425 Problem set #1 NGUYEN, THUAN 1/11. A vapor at the dew point and 200 kPa containing a mole fraction of 0.40 benzene (1) and0.60 toluene (2) and 100 kmol total is brought into contact with 110 kmol of a liquid at theboiling point containing a mole fraction of 0.30 benzene and 0.70 toluene. The two streamsare contacted in a single stage, and the outlet streams leave in equilibrium with each other.Assume constant molar overflow, calculate the amounts and compositions of the exit streams.Data: Vapor pressure, Psat, data: ln Psat = A  B/(T + C), where Psat is in kPa and T is in K. Compound A B CBenzene (1) 14.1603 2948.78  44.5633Toluene (2) 14.2515 3242.38  47.1806Problem 1: Correct, Code =4313336481Solutionx0 = 0.3, L0 = 110 kmol, x and y are mole fraction of benzene in the liquid and vapor phase, respectively.Equilibrium stageV2V1L0L1y2 = 0.4, V2 = 100 kmolFor CMO, L1 = L0 = 110 kmol, V2 = V1 = 100 kmol. Making a balance on benzene givesL0x0 + V2y2 = L1x1 + V1y1110(0.30) + 100(0.40) = 110x1 + 100y111x1 + 10y1 = 7.3  y1 = 0.73  1.1x1(E-1)Since the two streams V1 and L1 are in equilibrium, we havey1x1= 1200satP  200y1 = x1exp(14.1603  2948.78/(T  44.5633)) (E-2)1− y11− x1= 2200satP  200(1  y1) = (1  x1)exp(14.2515  3242.38/(T  47.1806)) (E-3)The three equations (E-1,2,3) can be solved for T, x1, and y1 either by graphical or numerical method.5.2 A liquid mixture containing 25 mol% benzene and 75 mol% ethyl alcohol, in which components are miscible in all proportions, is heated at a constant pressure of 1 atm from 60oC to 90oC. Using the spline command in Matlab to plot the following T-x-y experimentaldata:y, x = mole fraction of benzene in vapor and liquid phase, respectivelyT,oC 78.4 77.5 75 72.5 70 68.5 67.7 68.5 72.5 75 77.5 80.1y 0 0.0750.28 0.42 0.54 0.60 0.68 0.73 0.82 0.88 0.95 1.0x 0 0.0150.05 0.12 0.22 0.31 0.68 0.81 0.91 0.95 0.98 1.0Note: the following Matlab codes can plot the data using spline command:T=[78.4 77.5 75 72.5 70 68.5 67.7 68.5 72.5 75 77.5 80.1];y=[0 0.075 0.28 0.42 0.54 0.60 0.68 0.73 0.82 0.88 0.95 1.0];x=[0 0.015 0.05 0.12 0.22 0.31 0.68 0.81 0.91 0.95 0.98 1.0];ppx=spline(x,T);ppy=spline(y,T);xp=0:0.02:1;yp=xp;Tx=ppval(ppx,xp);Ty=ppval(ppy,yp);plot(xp,Tx,yp,Ty)grid onTitle('Txy data for benzene-ethyl alcohol at 1 atm')xlabel('x,y: mole fraction benzene')ylabel('T(^oC)')Determine: (a) the temperature where vaporization begins; (b) the composition of the firstbubble of vapor; (c) the composition of the residual liquid when 25 mol% has evaporated,assuming that all vapor formed is retained in the apparatus and is in equilibrium with theresidual liquid. (d) Repeat part (c) for 90 mol% vaporized. (e) Repeat part (d) if, after 25 mol% is vaporized as in part (c), the vapor formed is removed and an additional 35 mol% isvaporized by the same technique used in part