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Metabolic Equations- When doing an equation, you should always do the following first Copy down all the numbers in the problem Then convert what you need. This is usually mph to m/min and % grade to decimal, and weight to kg for running and walking and the others I’ll go over 1mph-26.8 m/min 1 MET= 3.5 ml/kg/min 1L= 5 Kcal Monarch wheel= 6 rev Watts= kg/m/min divided by 6.12 Kg/m/min= resistance/6/rpm Outline the unknown, and get the equationWalking: ml/kg/min= 3.5 + (m/min x .1) + (grade x m/min x 1.8)Running: ml/kg/min= 3.5 + (m/min x .2) + (grade x m/min x .9)Ergometer: ml/kg/min= 7 + kg/m/min x (1.8/bodyweight)Stepping= ml/kg/min = 1.33 x 1.8 x stepping rate x stepping height) + (.2 x stepping rate) Plug and chug Find time or calories if needed.Know I’ll go over each problem, so it all makes sense: Unfortunately I don’t have the problem sheet, butI have my work, so I’ll just go based on the work. I can kinda guess what the question was1. The problem was a typical running equation. It is asking for the MET he is working at. The variable it gave was 6.5 mph and 2.5% grade; it also gives his weight, but you only use weight if you are doing something with min or calories. Now you have to convert 6.5 mph to m/min by multiplying by 26.8, and 2.5% to decimal. The formula gives the answer in ml/kg/min, so you’ll have to convert this at the end to MET. Answer is 12 METS2. Now the client is walking and wants to know how long they have to walk to burn a certain number of calories. So now you have to use their weight. Write down all the variables. 2.5 mph, 5%, 165lbs, 300 kcal. Convert mph=m/min, 5% to decimal, and 165lb=kg. Now plug into formula and solve to ml/kg/min. Once you get this, which is 16.23ml/kg/min, you have to get min alone, so you have to cancel kg and ml. The reason for this is because we know 1L=5 kcal. So take 16.23 ml/kg/min x 75 kg (tocancel the kg in ml/kg/min), now you have 1217 ml/gl, then convert to L, so 1.217 L/min. This is absolute Vo2 in case you didn’t know. Know you now that 1L=5 kcal, so multiply it by 5 and you get 6.08kcal/min. This is how many calories he is burning per min. Wants to burn 300 kcal, so just divide 300 kcal/ 6.08 kcal//min and get 49.3 min.3. Is essentially the same as problem 2 and he’s walking. It’s asking for the grade. So get all the variables. 3.5 mph, 300 kcal, 45min, 150 lbs. Now if you look at the formula, you are missing two variables, the grade and the ml/kg/min, so you can’t really solve it. So you have to find ml/kg/min first. Basically whatyou did above, but working backwards. He wants to work for 45 min and burn 300 kcal, so he has to burn 300min/45 kcal, or 6.6 kcal/min. And this is 1.33 L/min, by 6.6 Kcal/min divided by 5 kcal (cause 1L is 5 Kcal). The convert 1.33 L/min to ml, and its 1333 ml/min. Finally take the weight in kg, 68.18kg, anddo 1333ml/min/68.18 kg, and you get 19.6 ml/kg/min. Now that you have the relative Vo2, you can plug it into the formula to get the grade. Convert mph to m/min and you get a decimal and convert to 3.9%4. Problem 3 is the hardest they will get, as you’re good now. They are running. It gives 11 MET and you are looking for the speed in mph. There is no grade. You have to convert MET to ml/kg/min by multiplying by 3.5, so 38.5 ml/kg/min. Since grade is 0, you can cancel out the last part of the equation. You solve and get m/min, so you convert it to mph by dividing by 26.8 and get 6.5 mph5. Is just asking for the watts. Resistance is 2, and 60 rpm. So you need the kg/m/min to do the formula forwatts. This is (resistance)(6)(rpm). 6 is a constant. This gives 720 kg/m/min, and now you plug it into the watts formula and get 117 watts.6. Now you have to use to formula for the ergometer. I think it was asking for how many calories he’d burn in 20 min. I believe it gave 600 kg/m/min and his weight of 185 lb. So convert weight to kg and plug into formula to get 19.84 ml/kg/min. So you need calories, so get rid of kg by multiplying 19.84 by 84.09 kg, and you get 1668 ml/min. Convert this to L/min, which is 1.6 L/min. Then to Kcal/min, which is 8.34 Kcal/ min. He wants to work for 20 min, so multiply 20 x 8.34 and get 166.8 Kcal.7. Ergometer formula again, but it gives watts instead of kg/m/min. Variable are 50 watts and 110 lb. Convert watts to kg/m/min with that formula on top of page to get 306 kg/m/min and the you can do the ergometer formula. This gives 18.016 ml/kg/min and it is asking for MET, so divide by 3.5 to get 5.14MET.8. This is a stepping problem. The variables 15 step/min, 25 cm, 150lb, and 20 min. You need the steppingrate in meters, so convert 25cm to .25 m. Plug into formula to get 15.4775 ml/kg/min. So you want howmany calories they are burning in 20 min. Get 15.4775 ml/kg/ min to Kcal/ min. Multiply by the kg, or 68.18 kg, to get 1055.15 ml/min. Convert to L/min, and get 1.055 L/min. Multiply by 5 to get 5.27 Kcal/min. And finally multiply by 20 min to get 105.52


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FSU PET 4551 - Metabolic Equations

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