-Below you will find practice questions for your 107 exam. Please keep inmind that these are only samples, can the number of questions, number ofquestions per topic and point values per question will likely be different.1. There is no SI base unit for area because: A) an area has no thickness; hence no physical standard can be builtB) we live in a three (not a two) dimensional world C) it is impossible to express square feet in terms of metersD) area can be expressed in terms of square metersE) area is not an important physical quantity 2. 1 m is equivalent to 3.281 ft. A cube with an edge of 1.5 ft has a volume of:A) 1.2  102 m3B) 9.6  10–2 m3C) 10.5 m3D) 9.5  10–2 m3E) 0.21 m33. Six million seconds is approximately:A) One dayB) Ten daysC) Two monthsD) One yearE) Ten years4. A car starts from Hither, goes 50 km in a straight line to Yon, immediately turns around, and returns to Hither. The time for this round trip is 2 hours. The magnitude of the average velocity of the car for this round trip is: A) 0 km/hrB) 50 km/hr C) 100 km/hr D) 200 km/hr E) cannot be calculated without knowing the acceleration 5. The coordinate of an object is given as a function of time by x = 7t – 3t2, where x is in meters and t is in seconds. Its average velocity over the interval from t = 0 to t = 2 s is:A) 5 m/sB) –5 m/sC) 11 m/sD) –11 m/sE) 1 m/s6. The coordinate of a particle in meters is given by x(t) = 16t – 3.0t3, where the time t is in seconds. The particle is momentarily at rest at t = 1A) 0.75 s B) 1.3 s C) 1.8 s D) 5.3 s E) 7.3 s7. This graph shows the position of a particle as a function of time. What is its instantaneous velocity at t = 7s?A) 3 m/sB) -3 m/sC) 12 m/sD) -12 m/sE) Need additional information.8. A ball rolls up a slope. At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0 cm/s. What is the magnitude of its average acceleration from the third to the eighth second? A) 2.5 cm/s2B) 4.0 cm/s2C) 5.0 cm/s2D) 6.0 cm/s2E) 6.67 cm/s29. The graph represents the straight line motion of a car. How far does the car travel between t = 2 seconds and t = 5 seconds? A) 4 m B) 12 m C) 24 m D) 36 m E) 60 m210. Displacement can be obtained from: A) the slope of an acceleration-time graph B) the slope of a velocity-time graph C) the area under an acceleration-time graph D) the area under a velocity-time graph E) the slope of an acceleration-time graph 11. A stone is thrown vertically upward with an initial speed of 19.5 m/s. It will rise to a maximum height of: A) 4.9 m B) 9.8 m C) 19.4 m D) 38.8 m E) none of these 12. An object is thrown vertically into the air. Which of the following five graphs represents the velocity (v) of the object as a function of the time (t)? The positive direction is taken to be upward.A) I B) II C) III D) IV E) V 313. The vector V3 in the diagram is equal to: A) V1−V2B) V1+V2 C) V2−V1 D) V1cos θ E) V1cosθ 14. Vectors A and B lie in the xy plane. We can deduce that A=B if: A) Ax2 + Ay2 = Bx2 + By2 B) Ax + Ay = Bx + By C) Ax = Bx and Ay = By D) Ay /Ax = By /Bx E) Ax = Ay and Bx = By 15. A vector has a component of 10 m in the +x direction, a component of 10 m in the +y direction, and a component of 5 m in the +z direction. The magnitude of this vector is: A) 0 m B) 15 mC) 20 mD) 25 mE) 225 m 16. The angle between A = −(25 m)^i + (45 m)^j and the positive x axis is: A) 29 B) 61 C) 119 D) 151 4E) 209 17. Let A = (2 m)^i + (6 m)^j – (3 m)^k and B = (4 m)^i + (2 m)^j + (1 m)^k. The vector difference D=A−B is: A) (6 m)^i + (8 m)^j – (2 m)^k B) (−2 m)^i + (4 m)^j – (4 m)^k C) (2 m)^i − (4 m)^j + (4 m)^k D) (8 m)^i + (12 m)^j – (3 m)^k E) none of these 18. In the diagram, A has magnitude 12 m and B has magnitude 8 m. The x component ofA +B is about: A) 1.5 m B) 4.5 m C) 12 m D) 15 m E) 20 m 19. Let A = (2 m)^i + (6 m)^j – (3 m)^k and B = (4 m)^i + (2 m)^j + (1 m)^k. Then A ∙B equals: A) (8 m)^i + (12 m)^j – (3 m)^k B) (12 m)^i − (14 m)^j – (20 m)^k C) 23 D) 17 E) none of these 20. Let S = (1 m)^i + (2 m)^j + (2 m)^k and T = (3 m)^i + (4 m)^k. The angle between these two vectors is given by: A) cos–1(14/15) B) cos–1(11/225) C) cos–1(104/225) D) cos–1(11/15) E) cannot be found since S and T do not lie in the same plane 521. Vectors A and B each have magnitude L. When drawn with their tails at the same point, the angle between them is 30. The magnitude of A ×B is: A) L2/2 B) L2 C) √3 L2/2 D) 2L2 E) none of these 22. Sally starts from home, walks 300 m east and then 500 m south, and arrives at her school. How far, in a straight line, is Sally’s school from her home?A) 300 mB) 500 mC) 580 mD) 640 mE) 800 m23. An object moves from x = –2.1 m, y = 3.7 m, z = 1.4 m to x = 3.3 m, y = –1.1 m, z = 4.2 m ina time of 5.3 s. What is its average velocity?A) (0.23 m/s)^i + (0.49 m/s)^j + (0.53 m/s)^kB) (5.4 m/s)^i − (4.8 m/s)^j + (2.8 m/s)^kC) (1.0 m/s)^i − (0.91 m/s)^j + (0.53 m/s)^kD) (1.0 m/s)^i + (0.91 m/s)^j + (1.1 m/s)^kE) −(1.0 m/s)^i + (0.91 m/s)^j + (0.53 m/s)^k24. The velocity of an object as a function of time is given by v = (12.5t − 7.2t2)^i + (4.3t3)^j. What is its acceleration as a function of time?A) a = (12.5 − 14.4t)^i + (12.9t2)^jB) a = (−7.2)^i + (4.3t)^jC) a = (5.3t)^i + (12.9t2)^jD) a = (−7.2)^i + (8.6t)^jE) a = (−14.4t)^i + (4.3t2)^j25. A bomber flying in level flight with constant velocity drops a bomb before it is over the target. Neglecting air resistance, which one of the following is NOT true? A) The bomber is over the target when the bomb strikes B) The acceleration of the bomb is constant C) The horizontal velocity of the plane equals the …