Prelab 7 : Bipolar Junction TransistorsOmkar H. RamachandranMarch 1, 20181 Biasing the Transistor1.1 Finding the Quiescent voltagesVB=15R2R1+ R2= 15 ×1057= 2.63 VVE= VB− 0.6 = 2.03 VFinally, at saturation, VCE= 0IC=VCC− VERC=15 − 2.032.74 × 103= 4.733 mAIE= IB+ IC= IC1 +1hfehfe∼ 200 for our transistor. Thus,IE= 4.733 ×1200+ 1∼ 4.756 mA1.2 Power EmittedP = I2ERL=4.756 × 10−32× 2.74 × 103= 61.9 mWwhich is well below that maximum PDof 625 mW1.3 What’s the point of the capacitors?C1and C2are set up to ensure that the bias condition is not affected by external components,as they will only pass AC current to the transistor.2 Transistor Amplifier2.1 Maximum hfeFrom the data sheet, we know that the maximum value of hfeis 20012.2 What is the maximum overall gain?G = −RCRE= −2.741= −2.742.3 What are the maximum and minimum output voltages?Since VE= VB− 0.6, min {VB} = 0.6 =⇒ min {Vout} = −1.644 V . The maximum voltageis dictated by the rail voltage, which is −15 V2.4 What are rinand rout?rin= REhfe= 200 × 103Ωrout= RC= 2.74 × 103Ω2.5 Gain for specific conditionWhen RL= 560 Ω,Vout= VE5602.74 × 103+ 560= 0.169VEThus 16.9% of the initial amplitude will be preserved3 Transistor Amplifier Dual StageRan out of time. Will complete by the time the lab starts4 Audio AmplifierAccording to the table, my phone’s output impedance is 3.45 Ω. Again, ran out of time.Will finish by the time the lab starts and resubmit.5 Lab Activities1. Step 6a seems to be the hardest, given that we’re working with a small load in parallel,thus increasing the possibility of noise2. I’m still very shaky on transistors in general. I’ll update this once I do more readingand