# UT PHY 317L - HW 1-solutions (6 pages)

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## HW 1-solutions

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- Pages:
- 6
- School:
- The University of Texas at Austin
- Course:
- Phy 317l - General Physics II

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mughawish am72963 HW 1 coker 56000 This print out should have 12 questions Multiple choice questions may continue on the next column or page find all choices before answering This assignment covers the material from Chapter 20 in the text Coulomb force electric field direct integration over charge distributions the dipole properties of the E field and electrical properties of materials 1 q a Q 2 2 d 2 a 1 d 3 d q a Q2 4 d a q a Q q 6 d 2a Q 5 d 001 10 0 points A particle of mass 17 g and charge 18 C is released from rest when it is 21 cm from a second particle of charge 17 C Determine the magnitude of the initial acceleration of the 17 g particle Correct answer 3668 37 m s2 Explanation Let m 17 g q 18 C 1 8 10 5 C d 21 cm 0 21 m Q 17 C 1 7 10 5 C ke 8 9875 109 N m2 C2 7 d 0 a 2 a 9 d correct 2 Explanation We have the force on charge q on the x axis due to charge Q on the y axis 8 d F and The force exerted on the particle is q Q ma d2 q Q a ke m d2 8 9875 109 N m2 C2 1 8 10 5 C 1 7 10 5 C 0 017 kg 0 21 m2 F ke 3668 37 m s2 002 10 0 points This question will help you review both basic vector concepts and basic calculus concepts Charge Q is on the y axis a distance a from the origin and charge q is on the x axis a distance d from the origin What is the value of d for which the x component of the force on q is the greatest 1 qQ r 4 0 r 2 p where r a2 d2 so the x component of the force on q is 1 4 0 1 4 0 1 4 0 Fx qQ cos r2 qQ d 2 2 a d a 2 d2 qQd 2 a d2 3 2 For maximum x component of the force Fx 0 is required so d Fx qQ a 2 2 d2 0 d 4 0 a2 d2 5 2 a 2 2 d2 0 a d 2 003 10 0 points A tiny charged sphere behaves like a point mughawish am72963 HW 1 coker 56000 charge when you are well away from the sphere Two small spheres carry electric charges of equal magnitudes There are equally spaced points a b and c which lie along the same line a c b What is the direction of the net electric field at each point due to these charges 1 a b c correct 2 a b a b c a b c c a 2 b c Explanation Since the field originates from positive charges and terminates

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